C P Road, Mumbai, India - 400101.
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Hindi Mother Tongue (Native)
Mumbai university 2018
Bachelor of Engineering (B.E.)
C P Road, Mumbai, India - 400101
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Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
CBSE, State
CBSE Subjects taught
Mathematics
Taught in School or College
No
State Syllabus Subjects taught
Mathematics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class I-V Tuition
1
Board
CBSE, State
CBSE Subjects taught
Mathematics
Taught in School or College
No
State Syllabus Subjects taught
Mathematics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
CBSE
CBSE Subjects taught
Mathematics
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
CBSE, State
CBSE Subjects taught
Mathematics
Taught in School or College
No
State Syllabus Subjects taught
Mathematics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
1
Board
CBSE
CBSE Subjects taught
Mathematics
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 8 Tuition
1
Board
CBSE, State
CBSE Subjects taught
Mathematics
Taught in School or College
No
State Syllabus Subjects taught
Mathematics
1. Which school boards of Class 12 do you teach for?
CBSE and State
2. Have you ever taught in any School or College?
No
3. Which classes do you teach?
I teach Class 10 Tuition, Class 11 Tuition, Class 12 Tuition, Class 8 Tuition, Class 9 Tuition and Class I-V Tuition Classes.
4. Do you provide a demo class?
Yes, I provide a free demo class.
5. How many years of experience do you have?
I have been teaching for less than a year.
Answered on 10/09/2019 Learn CBSE/Class 12/Mathematics/Unit I: Relations and Functions/NCERT Solutions/Exercise 1.1
It is given that
R = {(P, Q) : distance of the point P from the origin is same as the distance of the point Q from the origin},
Now, it is clear that
(P,P) ∈ R since the distance of point P from origin is always the same as the distance of the same point P from the origin.
Therefore, R is reflexive.
Now, Let us take (P,Q) ∈ R,
⇒ The distance of point P from origin is always the same as the distance of the same point Q from the origin.
⇒ The distance of point Q from origin is always the same as the distance of the same point P from the origin.
⇒ (Q,P)∈ R
Therefore, R is symmetric.
Now, Let (P,Q), (Q,S) ∈ R
⇒ The distance of point P and Q from origin is always the same as the distance of the same point Q and S from the origin.
⇒ The distance of points P and S from the origin is the same.
⇒ (P,S) ∈ R
Therefore, R is transitive.
Therefore, R is equivalence relation.
The set of all points related to P ≠ (0,0) will be those points whose distance from the origin is the same as the distance of point P from the origin.
So, if O(0,0) is the origin and OP = k, then the set of all points related to P is at a distance of k from the origin.
Therefore, this set of points forms a circle with the centre as the origin and this circle passes through point P.
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
CBSE, State
CBSE Subjects taught
Mathematics
Taught in School or College
No
State Syllabus Subjects taught
Mathematics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class I-V Tuition
1
Board
CBSE, State
CBSE Subjects taught
Mathematics
Taught in School or College
No
State Syllabus Subjects taught
Mathematics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
CBSE
CBSE Subjects taught
Mathematics
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
CBSE, State
CBSE Subjects taught
Mathematics
Taught in School or College
No
State Syllabus Subjects taught
Mathematics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
1
Board
CBSE
CBSE Subjects taught
Mathematics
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 8 Tuition
1
Board
CBSE, State
CBSE Subjects taught
Mathematics
Taught in School or College
No
State Syllabus Subjects taught
Mathematics
Answered on 10/09/2019 Learn CBSE/Class 12/Mathematics/Unit I: Relations and Functions/NCERT Solutions/Exercise 1.1
It is given that
R = {(P, Q) : distance of the point P from the origin is same as the distance of the point Q from the origin},
Now, it is clear that
(P,P) ∈ R since the distance of point P from origin is always the same as the distance of the same point P from the origin.
Therefore, R is reflexive.
Now, Let us take (P,Q) ∈ R,
⇒ The distance of point P from origin is always the same as the distance of the same point Q from the origin.
⇒ The distance of point Q from origin is always the same as the distance of the same point P from the origin.
⇒ (Q,P)∈ R
Therefore, R is symmetric.
Now, Let (P,Q), (Q,S) ∈ R
⇒ The distance of point P and Q from origin is always the same as the distance of the same point Q and S from the origin.
⇒ The distance of points P and S from the origin is the same.
⇒ (P,S) ∈ R
Therefore, R is transitive.
Therefore, R is equivalence relation.
The set of all points related to P ≠ (0,0) will be those points whose distance from the origin is the same as the distance of point P from the origin.
So, if O(0,0) is the origin and OP = k, then the set of all points related to P is at a distance of k from the origin.
Therefore, this set of points forms a circle with the centre as the origin and this circle passes through point P.
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