0Given that the cost price of 10 oranges is equal to the cost price of 1 kg of apples and the cost price of12 apples is equal to the cost price of 1 kg of oranges. If the selling price of 15 oranges is equal to the selling price of 1 kg of apples, then the selling price of 1 kg of oranges is equal to selling price of 1kg of apples. Assume that all the apples are identical and this holds true for the oranges as well.)
(a) 8 apples
(b) 9 apples
(c) 10 apples
(d) 12 apples
Answer:
Suppose weight of ‘x’ apples be equal to 1 kg
Weight of 'y' oranges be equal to 1 kg.
And let cost price and selling price of 1 apple be ‘C1’ and ‘S1’ respectively.
Similarly cost price and selling price of 1 orange be ‘C2’ and ‘S2’ respectively.
So according to Question,
10 × C2 = X × C1 ...(i)
Y × C2 = 12 × C1 ...(ii)
15 × S2 = X × S1 ...(iii)
And Suppose the selling price of 1 kg of oranges be equal to that of ‘A’ apples. (Which we have to find out )
So,
q × S2 = A × S1 ...(iv)
(I) ÷ (ii)
10/y = x/12
=> XY = 120 --(v)
And
(iii) ÷ (IV)
15/y = x /A
=> XY = 15A
From (v)
15A = 120
A = 8.
