Tollygunge, Kolkata, India - 700040
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5 Students Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
15
Board
ICSE, International Baccalaureate, CBSE
IB Subjects taught
Mathematics
Preferred class strength
One on one/ Private Tutions
CBSE Subjects taught
Mathematics
ICSE Subjects taught
Mathematics
Experience in School or College
I have taught online the students of India and USA up to 12 grade for 15 years.
Taught in School or College
Yes
Teaching Experience in detail in Class 10 Tuition
I am a retired Mechanical engineer. For over 15 years I am doing private tuition out of these 11 years for online tutoring in math. I use Skype,Bitpaper interactive whiteboard, scientific calculator and various graph programs.I explain step by step until the student understands thoroughly.I hold mock tests to prepare the students well before the exams.
11 Students Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
15
Board
ICSE, International Baccalaureate, CBSE
IB Subjects taught
Mathematics
Preferred class strength
One on one/ Private Tutions
CBSE Subjects taught
Mathematics
ICSE Subjects taught
Mathematics
Experience in School or College
I have taught online for 15 years.
Taught in School or College
Yes
Teaching Experience in detail in Class 9 Tuition
I am a retired Mechanical engineer.I have 15 years of experience of tutoring in math. for students up to class 12. Last 11 years I am doing online classes.I teach with skype, Bitpaper whiteboard, scientific calculator and different graphing programs.I am conversant with all the topics of math.I am able to teach algebra, geometry, trigonometry, Calculus, Descriptive Statistics.
5 Students Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
11
Board
ISC/ICSE, International Baccalaureate, CBSE
IB Subjects taught
Mathematics
Preferred class strength
One on one/ Private Tutions
ISC/ICSE Subjects taught
Mathematics
CBSE Subjects taught
Mathematics
Taught in School or College
No
Teaching Experience in detail in Class 11 Tuition
I am a retired Mechanical Engineer. I have over 11 years of experience as online tutor(Math.)I am able to tutor all boards. I am fully conversant with Algebra, Geometry, Trigonometry, Calculus , Descriptive statistics.I have taken over 12000 math. sessions and fully confident to tutor students up to Class 12.i teach with skype, Bitpaper white board, advanced scientific calculator and different graph programs.
4 Students Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
11
Board
ISC/ICSE, International Baccalaureate, CBSE
IB Subjects taught
Mathematics
Preferred class strength
One on one/ Private Tutions
ISC/ICSE Subjects taught
Mathematics
CBSE Subjects taught
Mathematics
Taught in School or College
No
Teaching Experience in detail in Class 12 Tuition
I have taught class 12 students for 5 years.
1 Student Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 8 Tuition
15
Board
ICSE, CBSE
Preferred class strength
One on one/ Private Tutions
CBSE Subjects taught
Mathematics
ICSE Subjects taught
Mathematics
Taught in School or College
No
Teaching Experience in detail in Class 8 Tuition
I have 5 years of experience for class8
4 Students Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 6 Tuition
5
Board
ICSE, CBSE
CBSE Subjects taught
Mathematics
ICSE Subjects taught
Mathematics
Taught in School or College
No
1 Student Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 7 Tuition
5
Board
ICSE, CBSE
CBSE Subjects taught
Mathematics
ICSE Subjects taught
Mathematics
Taught in School or College
No
4.5 out of 5 23 reviews
Sujit Chandraskear
Class 9 Tuition Board of Education:CBSE Preferred class strength:One on one/ Private Tutions CBSE Subject:Mathematics
"Many people say is teaching is slow, but that is what is needed for most children as it makes easier to understand his class and he is very clear when talking. Overall best teacher. "
Reply by Palak
Thank you for your review.This motivates me to teach better.
Sagnik Sen
Class 8 Tuition
"Good teacher & also a nice humble person. Explain mathematics in a lucid manner though charging higher side. Recommend highly. He connect very well to student. "
Reply by Palak
Thank you for your all kind words. This motivates me to do better in my classes.
Avi Chatterjee
Class 6 Tuition
"Palak Sir is excellent in making maths fun to learn, my son enjoyed every second of the the class and one of his long pending problem in understanding fraction was over in first 10 min and my son has started liking maths now. Highly recommended. "
Reply by Palak
Thank you.
Madiha
Class 9 Tuition
"The class was really pathetic. It was not at all a good experience studying/interacting with him. I hated it. "
Reply by Palak
I am really surprised to know that you did not like my teaching. You wanted me to explain compound interest problems. I solved as many as 5 problems. Never ever you mentioned you did not follow,when I asked you about your understanding. I tried to involve you in the congruence of triangles,but you hardly participated. At the end of the session I had to inform you about the payment. Normally it is discussed with parents. Since you told no one is available,I had to inform you. Prior to demo class I called you several times to know the topic for demo session,but you never picked. Can you explain why you told in the class you were following?
Vasantha
"Very good teacher explains all clearly and make sure you have understood everything over all extremely happy with his classes. "
Reply by Palak
Thank you madam for appreciating my work.It will definitely inspire me to do better.
Sandhya Avikal
"I am very happy with this teaching. I came to know about many new things which I was not able to understand in the class. I feel proud and blessed to have him as a tutor. He is a great tutor. "
Reply by Palak
Thank you for such a beautiful review,
Sheetal
"Fantastic and senior professor with clear concepts. Has a lot of patience and can deal with student very well. Very helpful and explains in different ways till the child understands. Sir has through knowledge and very adjusting to the needs of the student. Highly recommend sir. "
Reply by Palak
Thank you so much for writing so wonderful review.
Padma Cherukuri
Class 6 Tuition
I loved
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Teacher's Knowledge
Class Content
Reply by Palak
Thank you for your encouragement.
Harsifat Kaur anand
Class 9 Tuition
I loved
Teaching Method
Teacher's Knowledge
Reply by Palak
Thank you for your encouragement.
Harsifat Kaur
Class 9 Tuition
I loved
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Class Content
Teaching Method
Teacher's Knowledge
Reply by Palak
Thank you.
Sujit Rajadurai
Class 9 Tuition
I loved
Teaching Method
Teacher's Knowledge
Reply by Palak
Thank you for a good review.
Alisha KUMARI
Class 9 Tuition
I loved
Teaching Method
Reply by Palak
Thank you for your good feedback. I will try to improve further so that my teaching is student-friendly, and they can learn better.
Shoneil Sawant
Class 11 Tuition
I loved
Audio/Video Quality
Mona bedi
Class 10 Tuition
I loved
Class Content
Teacher's Knowledge
Teaching Method
Audio/Video Quality
Reply by Palak
Thank you for your positive feedback.I hope,I can continue teaching according to the needs of a student.
Aditi
Class 9 Tuition
I liked
Class Content
Teacher's Knowledge
Reply by Palak
Thank you for giving a positive feedback about my teaching.
Answered on 18/07/2019 Learn CBSE/Class 10/Mathematics/UNIT I: Number systems/Real numbers/NCERT Solutions/Exercise 1.1
Answered on 18/07/2019 Learn CBSE/Class 10/Mathematics/UNIT I: Number systems/Real numbers/NCERT Solutions/Exercise 1.1
Let a and b are two integers, where a>b, then according to Euclid division lemma a=bq+r where 0<=r<b, Here let b=6, then a=6q+r so 0<=r<6
When r=0, a=6q, when r=1,a=6q+1, for r=2, a=6q+2, for r=3, a=6q+3, for r=4, a=6q+4, for r=5, a=6q+5.here 6q,6q+2 and 6q+4 are divisible by 2, so even.
6q+1,6q+3 and 6q+5 are not divisible by 2. so they are odd.
Answered on 18/07/2019 Learn CBSE/Class 10/Mathematics/UNIT I: Number systems/Real numbers/NCERT Solutions/Exercise 1.4
(i)
(ii)
(iii)
(iv)
(v)
(vi)
For a terminating decimal denominator must be 2^mx5^n where m and n are integers.
For (i) 3125=5^5x1=5^5x2^0=2^0x5^5 So 13/3125 is a terminating decimal.
(ii)8=2^3x1=2^3x5^0 so 17/8 is a terminating decimal.
(iii)155=5x31. There is no factor of 2 here. So 64/155 is non terminating decimal.
(iv)1600=64x25=2^6x5^2. So 15/1600 is terminating decimal.
(v)343=7^3, no factors of 2 and 5. So 29/343 is non terminating decimal.
(vi) The denominator is 2^3x5^2. So 23/2^3x5^2 is a terminating decimal.
Answered on 18/07/2019 Learn CBSE/Class 10/Mathematics/UNIT I: Number systems/Real numbers/NCERT Solutions/Exercise 1.3
(i)Let is a rational number=. Squaring both sides ½=, So b^2=2a^2.So b^2 is divisible by 2 and b is divisible by 2. Let b=2c where c is an integer. Then b^2=4c^2, Hence 2a^2=4c^2. and a^2=2c^2.so a^2 is divisible by 2 and a is divisible by 2.This shows a and b have a common factor 2. But for a rational number a/b there cannot be a common factor other than 1.So this contradicts 1/√2 is rational. So it is an irrational number.
(ii) Let 7√5 is a rational number=a/b.
then√5=a/7b is a rational number. But we know√5 is irrational. So 7√5 is irrational.
(iii)Let 6+√2 is a rational number=a/b
then√2=(a/b)-6=(a-6b)/6 is a rational number.
This contradicts √2 is irrational.
So 6+√2 is irrational.
Answered on 18/07/2019 Learn CBSE/Class 10/Mathematics/UNIT I: Number systems/Real numbers/NCERT Solutions/Exercise 1.3
When the sum of two angles=90 degrees, they are called complementary angles. We can use following formula →sin(90-θ)=cosθ,cos(90-θ)=sinθ,tan(90-θ)=cotθ,cosec(90-θ)=secθ,sec(90-θ)=cosecθ We...
We know that Euclid's Division lemma states if a and b are two positive integers and a>b, then a=bq+r where q and r are two integers, where the value of r is given by 0<=r<b, This principle is...
To find cube root by estimation we divide a number into two groups and find ones and tens from each group. Example1):-Estimate cube root of 12167 Here we divide 12167 into two groups 12 and 167 Take...
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