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Java > Learn Java > Why Java doesnot have Pointer ?
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Why Java doesnot have Pointer ?

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Industry expert and professional lecturer/trainer

To avoid memory hacks and leaks it is an intentional decision taken by JAva Pioneers
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Corporate trainer with 11 years of experience, Founder of Study9

The reasons are Pointers are fundamentally unsafe. Java has a robust security model and disallows pointer arithmetic.Java ensures pointer access via indexed array. A big advantage of Java's indexed array access is that it detects and disallows out of bounds array access, which can be a major source...
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The reasons are Pointers are fundamentally unsafe. Java has a robust security model and disallows pointer arithmetic.Java ensures pointer access via indexed array. A big advantage of Java's indexed array access is that it detects and disallows out of bounds array access, which can be a major source of bugs. Java has the concept of References to objects,but it just doesn't call them pointers. Any normal object reference works as one of these. When you do String s="Hello"; you get what is effectively a pointer to a string object. read less
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Expert Tutor

Java does not have pointers. This was an intentional decision by the creators of Java, because most people would agree that having pointers creates a lot of potential for bugs in the code -- pointers can be quite confusing, especially to new programmers. Because arrays and strings are provided as class...
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Java does not have pointers. This was an intentional decision by the creators of Java, because most people would agree that having pointers creates a lot of potential for bugs in the code – pointers can be quite confusing, especially to new programmers. Because arrays and strings are provided as class types in Java, there is no need for pointers to those constructs. By not allowing pointers, Java provides effectively provides another level of abstraction to the programmer. read less
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Tutor - Maths and computer science

Because Java was built with safety in mind and pointers are a point of complexity(and thus failure) in a lot of programs if the developer is not careful. Java abstracts a number of things away from the developer to make things easier and safer for them, ie, garbage collection.
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Do remove the complexity in programming
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IT Professional Trainer working with a reputed Institute. Headquarters: Hyderabad

Yes. They're called "references".
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Java/J2EE, B.E./B.Tech/MCA SubjectsTraining

Pointers need so memory spaces at the runtime. to reduce the usage of memory spaces java does not support pointers. and also pointers take more time at the run time.
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Trainer

Java doesn't have pointer but has reference - which is more or less similar to it. but unlike c/C++, there's no separate pointer object (or variable). Each Java variable is a reference to an object
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Excel VBA Expert

The pointer is hidden and everyone should be happy about it
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Tutor

This isn't a simple question with a simple answer but here's the gist of it. Java doesn't give the programmer direct access to memory, therefore no pointers no malloc no free no realloc etc. This is done for safety reasons, it protects the programmer from tampering with things (in Java's mind at least)...
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This isn't a simple question with a simple answer but here's the gist of it. Java doesn't give the programmer direct access to memory, therefore no pointers no malloc no free no realloc etc. This is done for safety reasons, it protects the programmer from tampering with things (in Java's mind at least) they shouldn't. read less
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