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Overview

Excellent presentation skills and a strong ability to quickly
establish rapport with people from diverse backgrounds.
PGDCA in Computer Applications
3 Years of Experience in Tutoring CBSE Students
Knowledge for French Language
Excellent Interpersonal Communication Skills
NCC Cadet

Languages Spoken

Hindi Mother Tongue (Native)

English Proficient

Education

Pondicherry University Pursuing

Bachelor of Science (B.Sc.)

Address

Dilsukhnagar, Hyderabad, India - 500059

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Teaches

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

2

Board

CBSE

CBSE Subjects taught

Social science, Mathematics, English, Hindi, Science

Taught in School or College

Yes

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

2

Board

CBSE

CBSE Subjects taught

Social science, Mathematics, English, Hindi, Science

Taught in School or College

Yes

Class 6 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 6 Tuition

3

Board

CBSE, IGCSE, ICSE, International Baccalaureate, State

IB Subjects taught

Hindi, Science, English, Mathematics, Computers, Physical Education, French

CBSE Subjects taught

Science, Computers, Hindi, French, English, EVS, Mathematics, Social Science

ICSE Subjects taught

History, Geography, EVS, French, Mathematics, Computer Science, English, Physics, Chemistry, Hindi

IGCSE Subjects taught

Science, English, French, Hindi, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

French, English, Science, Hindi, EVS, Mathematics, Social science

Class 7 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 7 Tuition

3

Board

CBSE, IGCSE, ICSE, International Baccalaureate, State

IB Subjects taught

Hindi, Science, English, Mathematics, Computers, Physical Education, French

CBSE Subjects taught

Science, Computers, Hindi, French, English, EVS, Mathematics, Social Science

ICSE Subjects taught

History, Geography, EVS, French, Mathematics, Computer Science, English, Physics, Chemistry, Hindi

IGCSE Subjects taught

Science, English, French, Hindi, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

French, English, Science, Hindi, EVS, Mathematics, Social science

Class 8 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

3

Board

CBSE, IGCSE, ICSE, International Baccalaureate, State

IB Subjects taught

Hindi, Science, English, Mathematics, Computers, Physical Education, French

CBSE Subjects taught

Science, Computers, Hindi, French, English, EVS, Mathematics, Social Science

ICSE Subjects taught

History, Geography, EVS, French, Mathematics, Computer Science, English, Physics, Chemistry, Hindi

IGCSE Subjects taught

Science, English, French, Hindi, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

French, English, Science, Hindi, EVS, Mathematics, Social science

Class I-V Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class I-V Tuition

3

Board

CBSE, International Baccalaureate, ICSE, State, IGCSE

IB Subjects taught

English, Mathematics, Hindi, Science, Social studies, Computers, French

CBSE Subjects taught

Mathematics, Hindi, Science, French, EVS, English, Computers

ICSE Subjects taught

Mathematics, Science, Hindi, EVS, French, English, Social Studies

IGCSE Subjects taught

Hindi, English, Mathematics, Science

Taught in School or College

No

State Syllabus Subjects taught

Science, EVS, Mathematics, Hindi, French, Social Science, English

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

3

Board

International Baccalaureate, ISC/ICSE, CBSE, IGCSE, State

IB Subjects taught

Mathematics, Chemistry

ISC/ICSE Subjects taught

Mathematics, Chemistry

CBSE Subjects taught

Chemistry, Mathematics

IGCSE Subjects taught

Chemistry, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, Chemistry

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

3

Board

CBSE

CBSE Subjects taught

Chemistry, Mathematics

Taught in School or College

No

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 10 do you teach for?

CBSE

2. Do you have any prior teaching experience?

Yes

3. Which classes do you teach?

I teach Class 10 Tuition, Class 11 Tuition, Class 12 Tuition, Class 6 Tuition, Class 7 Tuition, Class 8 Tuition, Class 9 Tuition and Class I-V Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 2 years.

Contact

Answers by Ashish Singh (2)

Answered on 28/10/2018 Learn CBSE/Class 11/Science/Chemistry +1 CBSE/Class 11/Science/Chemistry/Some Basic Concepts of Chemistry

Calcium carbonate reacts with aqueous HCl according to the reaction CaC03 (s) + 2HCl (aq) ———->CaCl2... ...more

Calcium carbonate reacts with aqueous HCl according to the reaction

CaC03 (s) + 2HCl (aq) ———->CaCl2 (aq) +C02(g) +H2O(l).

What mass of CaC03 is required to react completely with 25 mL of 0.75 M HCl?

1000 mL of 0.75 M HCl have 0.75 mol of HCl = 0.75×36.5 g = 24.375 g∴ Mass of HCl in 25mL of 0.75 M HCl = 24.375/1000 × 25 g = 0.6844 gFrom the given chemical equation,CaCO3 (s) + 2HCl (aq) → CaCl2(aq) + CO2(g) + H2O(l)2 mol of HCl i.e. 73 g HCl react completely with 1 mol of CaCO3... ...more

1000 mL of 0.75 M HCl have 0.75 mol of HCl = 0.75×36.5 g = 24.375 g
∴ Mass of HCl in 25mL of 0.75 M HCl = 24.375/1000 × 25 g = 0.6844 g
From the given chemical equation,
CaCO3 (s) + 2HCl (aq) → CaCl2(aq) + CO2(g) + H2O(l)
2 mol of HCl i.e. 73 g HCl react completely with 1 mol of CaCO3 i.e. 100g
∴ 0.6844 g HCl reacts completely with CaCO3 = 100/73 × 0.6844 g = 0.938 g

Answers 1 Comments
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Answered on 25/10/2018 Learn Hydrocarbons +1 CBSE/Class 11/Science/Chemistry

The relative reactivity of 1°, 2° and 3° hydrogens towards chlorination is 1: 3.8 : 5. Calculate... ...more
The relative reactivity of 1°, 2° and 3° hydrogens towards chlorination is 1: 3.8 : 5. Calculate the percentages of all monochlorinated products obtained from 2-methylbutane.

Relative amount of monochlorinated product = Number of hydrogen X relative reactivity For (1°) monochlorinated product = 9x1 = 9(2°) monochlorinated product = 2x 3.8 = 7.6 (3°) monochlorinatedproduct = 1x3 = 5Total amount of monochlorinated compounds = 9 + 7.6+ 5 = 21.6 % of 1° monochlorinated... ...more

Relative amount of monochlorinated product = Number of hydrogen X relative reactivity For (1°) monochlorinated product = 9x1 = 9
(2°) monochlorinated product = 2x 3.8 = 7.6 (3°) monochlorinated
product = 1x3 = 5
Total amount of monochlorinated compounds = 9 + 7.6+ 5 = 21.6

% of 1° monochlorinated product = 9x100/21.6 =41.67
% of 2° monochlorinated product =7.6x100/21.6 =35.18
% of 3° monochlorinated product =5x100/21.6 =23.15

Answers 1 Comments
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Contact

Teaches

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

2

Board

CBSE

CBSE Subjects taught

Social science, Mathematics, English, Hindi, Science

Taught in School or College

Yes

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

2

Board

CBSE

CBSE Subjects taught

Social science, Mathematics, English, Hindi, Science

Taught in School or College

Yes

Class 6 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 6 Tuition

3

Board

CBSE, IGCSE, ICSE, International Baccalaureate, State

IB Subjects taught

Hindi, Science, English, Mathematics, Computers, Physical Education, French

CBSE Subjects taught

Science, Computers, Hindi, French, English, EVS, Mathematics, Social Science

ICSE Subjects taught

History, Geography, EVS, French, Mathematics, Computer Science, English, Physics, Chemistry, Hindi

IGCSE Subjects taught

Science, English, French, Hindi, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

French, English, Science, Hindi, EVS, Mathematics, Social science

Class 7 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 7 Tuition

3

Board

CBSE, IGCSE, ICSE, International Baccalaureate, State

IB Subjects taught

Hindi, Science, English, Mathematics, Computers, Physical Education, French

CBSE Subjects taught

Science, Computers, Hindi, French, English, EVS, Mathematics, Social Science

ICSE Subjects taught

History, Geography, EVS, French, Mathematics, Computer Science, English, Physics, Chemistry, Hindi

IGCSE Subjects taught

Science, English, French, Hindi, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

French, English, Science, Hindi, EVS, Mathematics, Social science

Class 8 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

3

Board

CBSE, IGCSE, ICSE, International Baccalaureate, State

IB Subjects taught

Hindi, Science, English, Mathematics, Computers, Physical Education, French

CBSE Subjects taught

Science, Computers, Hindi, French, English, EVS, Mathematics, Social Science

ICSE Subjects taught

History, Geography, EVS, French, Mathematics, Computer Science, English, Physics, Chemistry, Hindi

IGCSE Subjects taught

Science, English, French, Hindi, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

French, English, Science, Hindi, EVS, Mathematics, Social science

Class I-V Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class I-V Tuition

3

Board

CBSE, International Baccalaureate, ICSE, State, IGCSE

IB Subjects taught

English, Mathematics, Hindi, Science, Social studies, Computers, French

CBSE Subjects taught

Mathematics, Hindi, Science, French, EVS, English, Computers

ICSE Subjects taught

Mathematics, Science, Hindi, EVS, French, English, Social Studies

IGCSE Subjects taught

Hindi, English, Mathematics, Science

Taught in School or College

No

State Syllabus Subjects taught

Science, EVS, Mathematics, Hindi, French, Social Science, English

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

3

Board

International Baccalaureate, ISC/ICSE, CBSE, IGCSE, State

IB Subjects taught

Mathematics, Chemistry

ISC/ICSE Subjects taught

Mathematics, Chemistry

CBSE Subjects taught

Chemistry, Mathematics

IGCSE Subjects taught

Chemistry, Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics, Chemistry

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

3

Board

CBSE

CBSE Subjects taught

Chemistry, Mathematics

Taught in School or College

No

No Reviews yet!

Answers by Ashish Singh (2)

Answered on 28/10/2018 Learn CBSE/Class 11/Science/Chemistry +1 CBSE/Class 11/Science/Chemistry/Some Basic Concepts of Chemistry

Calcium carbonate reacts with aqueous HCl according to the reaction CaC03 (s) + 2HCl (aq) ———->CaCl2... ...more

Calcium carbonate reacts with aqueous HCl according to the reaction

CaC03 (s) + 2HCl (aq) ———->CaCl2 (aq) +C02(g) +H2O(l).

What mass of CaC03 is required to react completely with 25 mL of 0.75 M HCl?

1000 mL of 0.75 M HCl have 0.75 mol of HCl = 0.75×36.5 g = 24.375 g∴ Mass of HCl in 25mL of 0.75 M HCl = 24.375/1000 × 25 g = 0.6844 gFrom the given chemical equation,CaCO3 (s) + 2HCl (aq) → CaCl2(aq) + CO2(g) + H2O(l)2 mol of HCl i.e. 73 g HCl react completely with 1 mol of CaCO3... ...more

1000 mL of 0.75 M HCl have 0.75 mol of HCl = 0.75×36.5 g = 24.375 g
∴ Mass of HCl in 25mL of 0.75 M HCl = 24.375/1000 × 25 g = 0.6844 g
From the given chemical equation,
CaCO3 (s) + 2HCl (aq) → CaCl2(aq) + CO2(g) + H2O(l)
2 mol of HCl i.e. 73 g HCl react completely with 1 mol of CaCO3 i.e. 100g
∴ 0.6844 g HCl reacts completely with CaCO3 = 100/73 × 0.6844 g = 0.938 g

Answers 1 Comments
Dislike Bookmark

Answered on 25/10/2018 Learn Hydrocarbons +1 CBSE/Class 11/Science/Chemistry

The relative reactivity of 1°, 2° and 3° hydrogens towards chlorination is 1: 3.8 : 5. Calculate... ...more
The relative reactivity of 1°, 2° and 3° hydrogens towards chlorination is 1: 3.8 : 5. Calculate the percentages of all monochlorinated products obtained from 2-methylbutane.

Relative amount of monochlorinated product = Number of hydrogen X relative reactivity For (1°) monochlorinated product = 9x1 = 9(2°) monochlorinated product = 2x 3.8 = 7.6 (3°) monochlorinatedproduct = 1x3 = 5Total amount of monochlorinated compounds = 9 + 7.6+ 5 = 21.6 % of 1° monochlorinated... ...more

Relative amount of monochlorinated product = Number of hydrogen X relative reactivity For (1°) monochlorinated product = 9x1 = 9
(2°) monochlorinated product = 2x 3.8 = 7.6 (3°) monochlorinated
product = 1x3 = 5
Total amount of monochlorinated compounds = 9 + 7.6+ 5 = 21.6

% of 1° monochlorinated product = 9x100/21.6 =41.67
% of 2° monochlorinated product =7.6x100/21.6 =35.18
% of 3° monochlorinated product =5x100/21.6 =23.15

Answers 1 Comments
Dislike Bookmark

Contact

Ashish Singh conducts classes in Class 10 Tuition, Class 11 Tuition and Class 12 Tuition. Ashish is located in Dilsukhnagar, Hyderabad. Ashish takes at students Home and Regular Classes- at his Home. He has 3 years of teaching experience . Ashish is pursuing Bachelor of Science (B.Sc.) from Pondicherry University. He is well versed in English and Hindi.

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