Sector 48, Faridabad, India - 121001.
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Hindi Mother Tongue (Native)
English Proficient
Manav rachna university 2018
Master of Science (M.Sc.)
FCA-780, Gali Number 5, Buadh Colony, Pocket A, Sanjay Gandhi Memorial Nagar, Sector 48
Sector 48, Faridabad, India - 121001
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Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
2
Board
CBSE
CBSE Subjects taught
Chemistry
Taught in School or College
No
Teaching Experience in detail in Class 12 Tuition
I am a post graduate in chemistry and taking tutions since 2 years. I am through with my chemistry concepts.
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
1
Board
CBSE
CBSE Subjects taught
Chemistry
Taught in School or College
No
4.9 out of 5 7 reviews
Mohit
"As he had taught me. She explains things with real life examples. The pattern to test after each unit was really helpful for examination."
Ankit Sharma
"Her hand in chemistry is very well. She has her own concept to teach the weak student. She is a worth chemistry teacher.. "
Reply by Saloni
Thankyou so much Ankit. Means a lot to listen from you.
Hari Prasad
"Saloni madam is one of the best teachers I have seen. She is very good with examples. She starts with basics and makes you understand complex things very easily. Her problem solving skills are excellent. She is a kind and good hearted soul. I bet you won't regret after taking tuition from her. "
Reply by Saloni
Thankyou Hari sir. I am overwhelmed to listen from you.
Jagriti
"From past 3 years she serves as a teacher. She is actually a brilliant and intellectual person. But teaching as a profession is not limited to just giving knowledge, one should be acquainted to shape and mould students for there golden future, and this point of time she (saloni goyal) is well organised in her own. She is enthusiast and good learner as well. My kids are her students and I know she is best. Believe is the first key to any path choosen. Thanks. "
Reply by Saloni
Thankyou maam. Ur kids were too attentive n hardworking. I just pushed them a little bit.
1. Which school boards of Class 12 do you teach for?
CBSE
2. Have you ever taught in any School or College?
No
3. Which classes do you teach?
I teach Class 11 Tuition and Class 12 Tuition Classes.
4. Do you provide a demo class?
Yes, I provide a free demo class.
5. How many years of experience do you have?
I have been teaching for 2 years.
Answered on 10/02/2019 Learn CBSE/Class 11/Science/Chemistry/Redox Reactions
Answered on 09/02/2019 Learn CBSE/Class 11
Answered on 28/01/2019 Learn CBSE/Class 11/Science/Chemistry/Unit 10-s -Block Elements (Alkali and Alkaline Earth Metals)
Answered on 28/01/2019 Learn CBSE/Class 11/Science/Chemistry/Unit 10-s -Block Elements (Alkali and Alkaline Earth Metals)
a) Acc to fajans rule, if the size of cation is small and anion is large then cation distorts the electron cloud of the anion making it polarised and more covalent. in this case Li+ (cation) is small in size and out of I- and F-, flourine is small anion and iodine is large anion. so as LiI will show polarisation it would be covalent.
b) lattice enthalpy is the enrgy to break out bonds to release atoms. as Li is small and F itself is small so the bond will be small and thus more energy will be required to break the bond and thus the enthapy would be higher.
Answered on 28/01/2019 Learn CBSE/Class 11/Science/Chemistry/Unit 10-s -Block Elements (Alkali and Alkaline Earth Metals)
a) alkali metals have only 1 electron in their last valence shell so thats why they show +1 oxidation state by attaining the noble gas configuration.
b) if the electrons are single in the last shell they possess very high energy so as the metal gets heated up they excite to the higher energy level by attaining some energy and when they re-emit the absorbed energy the color is imparted.
c) Li+ is very small in size. and its in general that a smaller anion is stablized by smaller cation. so being oxide O2- and peroxide 022- the smaller and the larger anion respectively. therefore Li+ will form oxide not superoxide.
d) reducing agents are those which reduces others but oxidise themselves. oxidation is loosing of electron so because Li readily forms Li+ on loosing one electron thus is a reducing agent.
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
2
Board
CBSE
CBSE Subjects taught
Chemistry
Taught in School or College
No
Teaching Experience in detail in Class 12 Tuition
I am a post graduate in chemistry and taking tutions since 2 years. I am through with my chemistry concepts.
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
1
Board
CBSE
CBSE Subjects taught
Chemistry
Taught in School or College
No
4.9 out of 5 7 reviews
Mohit
"As he had taught me. She explains things with real life examples. The pattern to test after each unit was really helpful for examination."
Ankit Sharma
"Her hand in chemistry is very well. She has her own concept to teach the weak student. She is a worth chemistry teacher.. "
Reply by Saloni
Thankyou so much Ankit. Means a lot to listen from you.
Hari Prasad
"Saloni madam is one of the best teachers I have seen. She is very good with examples. She starts with basics and makes you understand complex things very easily. Her problem solving skills are excellent. She is a kind and good hearted soul. I bet you won't regret after taking tuition from her. "
Reply by Saloni
Thankyou Hari sir. I am overwhelmed to listen from you.
Jagriti
"From past 3 years she serves as a teacher. She is actually a brilliant and intellectual person. But teaching as a profession is not limited to just giving knowledge, one should be acquainted to shape and mould students for there golden future, and this point of time she (saloni goyal) is well organised in her own. She is enthusiast and good learner as well. My kids are her students and I know she is best. Believe is the first key to any path choosen. Thanks. "
Reply by Saloni
Thankyou maam. Ur kids were too attentive n hardworking. I just pushed them a little bit.
Answered on 10/02/2019 Learn CBSE/Class 11/Science/Chemistry/Redox Reactions
Answered on 09/02/2019 Learn CBSE/Class 11
Answered on 28/01/2019 Learn CBSE/Class 11/Science/Chemistry/Unit 10-s -Block Elements (Alkali and Alkaline Earth Metals)
Answered on 28/01/2019 Learn CBSE/Class 11/Science/Chemistry/Unit 10-s -Block Elements (Alkali and Alkaline Earth Metals)
a) Acc to fajans rule, if the size of cation is small and anion is large then cation distorts the electron cloud of the anion making it polarised and more covalent. in this case Li+ (cation) is small in size and out of I- and F-, flourine is small anion and iodine is large anion. so as LiI will show polarisation it would be covalent.
b) lattice enthalpy is the enrgy to break out bonds to release atoms. as Li is small and F itself is small so the bond will be small and thus more energy will be required to break the bond and thus the enthapy would be higher.
Answered on 28/01/2019 Learn CBSE/Class 11/Science/Chemistry/Unit 10-s -Block Elements (Alkali and Alkaline Earth Metals)
a) alkali metals have only 1 electron in their last valence shell so thats why they show +1 oxidation state by attaining the noble gas configuration.
b) if the electrons are single in the last shell they possess very high energy so as the metal gets heated up they excite to the higher energy level by attaining some energy and when they re-emit the absorbed energy the color is imparted.
c) Li+ is very small in size. and its in general that a smaller anion is stablized by smaller cation. so being oxide O2- and peroxide 022- the smaller and the larger anion respectively. therefore Li+ will form oxide not superoxide.
d) reducing agents are those which reduces others but oxidise themselves. oxidation is loosing of electron so because Li readily forms Li+ on loosing one electron thus is a reducing agent.
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