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Explain the following:
(a) Lithium iodide is more covalent than lithium fluoride.
(b) Lattice enthalpy of LiF is maximum among all the alkali metal halides.

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a) Acc to fajans rule, if the size of cation is small and anion is large then cation distorts the electron cloud of the anion making it polarised and more covalent. in this case Li+ (cation) is small in size and out of I- and F-, flourine is small anion and iodine is large anion. so as LiI will show...
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a) Acc to fajans rule, if the size of cation is small and anion is large then cation distorts the electron cloud of the anion making it polarised and more covalent. in this case Li+ (cation) is small in size and out of  I- and F-, flourine is small anion and iodine is large anion. so as LiI will show polarisation it would be covalent.

b) lattice enthalpy is the enrgy to break out bonds to release atoms. as Li is small and F itself is small so the bond will be small and thus more energy will be required to break the bond and thus the enthapy would be higher.

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(a) This is due to large electronegativity difference between Li and F and small size of Flourine, it has partial polar character than Lithium Iodide
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