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Class 12 Tuition > Learn Class XI-XII Tuition (PUC) > When a current carrying conductor experiences highest...
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When a current carrying conductor experiences highest mechanical force , then find out the angle between the direction of the conductor and the magnetic field?

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Native English Speaker with 32 years experience in teaching English and communication skills.

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The force on a charged particle moving in a magnetic field is at its maximum when the particle is moving at right angles to the direction of the magnetic field and zero when the particle is moving parallel to the field. The direction of the drift velocity of electrons in a conductor is along the length...
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The force on a charged particle moving in a magnetic field is at its maximum when the particle is moving at right angles to the direction of the magnetic field and zero when the particle is moving parallel to the field. The direction of the drift velocity of electrons in a conductor is along the length of the conductor. Thus, the magnitude of the force on a current-carrying conductor in a magnetic field varies with the angle between the direction of the length of the conductor and the direction of the magnetic field. The force is at a maximum when the angle between the conductor and the magnetic field is 90° and zero when the conductor lies parallel to the field. read less
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The direction of the force on a current-carrying conductor sitting in a magnetic field is found by Fleming’s Left Hand Rule, as previously described. It should also be clear that neither a charge travelling parallel to a magnetic field nor a current-carrying conductor lying parallel to a magnetic field...
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The direction of the force on a current-carrying conductor sitting in a magnetic field is found by Fleming’s Left Hand Rule, as previously described. It should also be clear that neither a charge travelling parallel to a magnetic field nor a current-carrying conductor lying parallel to a magnetic field will experience any force due to the field, since for both, sin q = 0. read less
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90. sine is max when they are perpendicular
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i am a Software Engineer in capgemini at PSN,Bangalore,Whitefield and i want a part time teaching job

90 degree. As we know mechanical force F=i.dl.B.Sinx. Where x is the angle between current element vector dl and magnetic field vector B. When sinx is maximum mechanical force will be maximum. As we know max value of sinx is 1 at x=90 degree. So angle between conductor and magnetic field is 90 degree...
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90 degree. As we know mechanical force F=i.dl.B.Sinx. Where x is the angle between current element vector dl and magnetic field vector B. When sinx is maximum mechanical force will be maximum. As we know max value of sinx is 1 at x=90 degree. So angle between conductor and magnetic field is 90 degree in this case.Here current element is infinitesemal straight part of conductor.If conductor is not straight then take a virtual line in between ends of conductor now we will treat it as straight conductor of length as virtual straight line. I could explain more about the counter part of curve shape but it is difficult to text here. Thanks read less
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In this case, follow, F= iL X B i.e. F = iLB Sin ?. When ? is 900, i.e. when the current carrying conductor is placed perpendicular to the direction of the magnetic field, then it experiences maximum force, given by F = iLB.
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F is proportional to sin(theta). So max force occurs when theta = 90 degrees. Theta is the angle between conductor and magnetic field.
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