Begur Road, Bangalore, India - 560068.
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English Proficient
Hindi Proficient
DDU 2008
Bachelor of Commerce (B.Com.)
ITM Gorakhpur 2011
Master of Business Administration (M.B.A.)
Begur Road, Bangalore, India - 560068
ID Verified
Phone Verified
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D
Delhi Public School
Electronic City, Bangalore
N
Narayana E-Techno School
Kammanahalli Sena Vihar, Bangalore
S
Sri Chaitanya Techno School
Arunodaya Nagar, Hayathnagar_Khalsa
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Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
10
Board
CBSE, ISC/ICSE
Preferred class strength
One on one/ Private Tutions, Group Classes
ISC/ICSE Subjects taught
Accounts
CBSE Subjects taught
Accountancy
Taught in School or College
Yes
Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in BCom Tuition
5
BCom Subject
Financial Accounting, Cost Accounting
Type of class
Crash Course, Regular Classes
Class strength catered to
One on one/ Private Tutions, Group Classes
Taught in School or College
Yes
Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
10
Board
CBSE, ISC/ICSE
Preferred class strength
One on one/ Private Tutions, Group Classes
ISC/ICSE Subjects taught
Accounts
CBSE Subjects taught
Accountancy
Taught in School or College
Yes
1. Which school boards of Class 12 do you teach for?
CBSE and ISC/ICSE
2. Have you ever taught in any School or College?
Yes
3. Which classes do you teach?
I teach BCom Tuition, Class 11 Tuition and Class 12 Tuition Classes.
4. Do you provide a demo class?
Yes, I provide a free demo class.
5. How many years of experience do you have?
I have been teaching for 10 years.
QUESTIONS: 1.Define profit centre. Ans: Profit Centre is a part of business accountable for costs and revenues. State the objective of Cost Accounting. Ans: Objectives of Cost Accounting The...
QUESTIONS: Define Partnership Deed. Answer: A partnership deed is an agreement among the partners which contains ai! the terms of the Partnership. It generally contains the details about all the...
Name some notable economists who estimated India’s per capita income during the colonial period. Ans: The following economists estimated India’s per capita income during the colonial...
Answered on 03 Jul Learn CBSE/Class 9/Mathematics/Geometry/Quadrilaterals
Given: In square ABCD, AK = BL = CM = DN.
To prove: KLMN is a square.
In square ABCD,
AB = BC = CD = DA
And, AK = BL = CM = DN
(All sides of a square are equal.) (Given)
So, AB - AK = BC - BL = CD - CM = DA - DN
⇒ KB = CL = DM = AN.......... (1)
In △NAKand△KBL
∠NAK=∠KBL=900 (Each angle of a square is a right angle.)
AK=BL (Given)
AN=KB [From (1)]
So, by SAS congruence criteria,
\(\triangle NAK ≅ \triangle KBL \)
⇒NK=KL (Cpctc ...(2)
Similarly,
\(\triangle MDN≅ \triangle NAK \)
\(\triangle DNM≅ \triangle CML \)
\(\triangle MCL≅ \triangle LBK \)
\(\rightarrow MN = NK and \angle DNM=\angle KNA \) (Cpctc )… 3)
MN = JM and ∠DNM=∠CML (Cpctc )… 4)
ML = LK and ∠CML=∠BLK (Cpctc )… (5)
From (2), (3), (4) and (5), we get
NK = KL = MN = ML…….....(6)
And, ∠DNM=∠AKN=∠KLB=∠LMC
Now,
In △NAK
∠NAK=900
Let ∠AKN=x0
So, ∠DNK=900+x0 (Exterior angles equals sum of interior opposite angles.)
⇒∠DNM+∠MNK=900+x0
⇒x0+∠MNK=900+x0
⇒ ∠MNK=900
Similarly,
∠NKL=∠KLM=∠LMN=900 ...(7)
Using (6) and (7), we get
All sides of quadrilateral KLMN are equal and all angles are \ ( 90^0 \)
So, KLMN is a square.
Answered on 03 Jul Learn CBSE/Class 9/Mathematics/Geometry/Construction
It is given that AB: BC: CA = 3: 4: 5
3x + 4x + 5x = 12
12x = 12
x = 1
AB = 3 cm, BC = 4 cm and CA = 5 cm
Steps of construction:
(1) Draw a sufficiently long line segment using a ruler.
(2) Locate points A and B on it such that AB = 3 cm.
(3) With A as the centre and radius 5 cm, draw an arc.
(4) With B as the centre and radius 4 cm, draw another arc that cuts the previous arc at C.
(5) Join AC and BC.
Then, ABC is the required triangle.
Answered on 03 Jul Learn CBSE/Class 9/Mathematics/Geometry/Construction
Steps of construction:
1. Draw a line segment PQ = 11.6 cm.
2. Construct an angle of 45° and bisect it to get ∠QPX.
3. Construct an angle of 60° and bisect it to get ∠PQY.
4. The ray XP and YQ intersect at A.
5. Draw the right bisectors of AP and AQ, cutting PQ at B and C, respectively.
6. Join AB and AC.
Thus, △ABC is the required triangle.
Answered on 01 Jul Learn CBSE/Class 9/Mathematics/Geometry/Quadrilaterals
Answered on 01 Jul Learn CBSE/Class 9/Mathematics/Geometry/Construction
Given: In ∆ABC
AB + BC + CA = 10 cm, ∠B = 60° and ∠C = 45°.
Required: To construct ∆ABC.
Steps of Construction :
1. Draw DE = 10 cm
2. At D, construct ∠EDP = 12 of 60°= 30° and at E, construct ∠DEQ =12 of 45° = 22 12∘
3. Let DP and EQ meet at A.
4. Draw perpendicular bisector of AD to meet DE at B.
5. Draw perpendicular bisector of AE to meet DE at C.
6. Join AB and AC. Thus, ABC is the required triangle.
Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
10
Board
CBSE, ISC/ICSE
Preferred class strength
One on one/ Private Tutions, Group Classes
ISC/ICSE Subjects taught
Accounts
CBSE Subjects taught
Accountancy
Taught in School or College
Yes
Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in BCom Tuition
5
BCom Subject
Financial Accounting, Cost Accounting
Type of class
Crash Course, Regular Classes
Class strength catered to
One on one/ Private Tutions, Group Classes
Taught in School or College
Yes
Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
10
Board
CBSE, ISC/ICSE
Preferred class strength
One on one/ Private Tutions, Group Classes
ISC/ICSE Subjects taught
Accounts
CBSE Subjects taught
Accountancy
Taught in School or College
Yes
Answered on 03 Jul Learn CBSE/Class 9/Mathematics/Geometry/Quadrilaterals
Given: In square ABCD, AK = BL = CM = DN.
To prove: KLMN is a square.
In square ABCD,
AB = BC = CD = DA
And, AK = BL = CM = DN
(All sides of a square are equal.) (Given)
So, AB - AK = BC - BL = CD - CM = DA - DN
⇒ KB = CL = DM = AN.......... (1)
In △NAKand△KBL
∠NAK=∠KBL=900 (Each angle of a square is a right angle.)
AK=BL (Given)
AN=KB [From (1)]
So, by SAS congruence criteria,
\(\triangle NAK ≅ \triangle KBL \)
⇒NK=KL (Cpctc ...(2)
Similarly,
\(\triangle MDN≅ \triangle NAK \)
\(\triangle DNM≅ \triangle CML \)
\(\triangle MCL≅ \triangle LBK \)
\(\rightarrow MN = NK and \angle DNM=\angle KNA \) (Cpctc )… 3)
MN = JM and ∠DNM=∠CML (Cpctc )… 4)
ML = LK and ∠CML=∠BLK (Cpctc )… (5)
From (2), (3), (4) and (5), we get
NK = KL = MN = ML…….....(6)
And, ∠DNM=∠AKN=∠KLB=∠LMC
Now,
In △NAK
∠NAK=900
Let ∠AKN=x0
So, ∠DNK=900+x0 (Exterior angles equals sum of interior opposite angles.)
⇒∠DNM+∠MNK=900+x0
⇒x0+∠MNK=900+x0
⇒ ∠MNK=900
Similarly,
∠NKL=∠KLM=∠LMN=900 ...(7)
Using (6) and (7), we get
All sides of quadrilateral KLMN are equal and all angles are \ ( 90^0 \)
So, KLMN is a square.
Answered on 03 Jul Learn CBSE/Class 9/Mathematics/Geometry/Construction
It is given that AB: BC: CA = 3: 4: 5
3x + 4x + 5x = 12
12x = 12
x = 1
AB = 3 cm, BC = 4 cm and CA = 5 cm
Steps of construction:
(1) Draw a sufficiently long line segment using a ruler.
(2) Locate points A and B on it such that AB = 3 cm.
(3) With A as the centre and radius 5 cm, draw an arc.
(4) With B as the centre and radius 4 cm, draw another arc that cuts the previous arc at C.
(5) Join AC and BC.
Then, ABC is the required triangle.
Answered on 03 Jul Learn CBSE/Class 9/Mathematics/Geometry/Construction
Steps of construction:
1. Draw a line segment PQ = 11.6 cm.
2. Construct an angle of 45° and bisect it to get ∠QPX.
3. Construct an angle of 60° and bisect it to get ∠PQY.
4. The ray XP and YQ intersect at A.
5. Draw the right bisectors of AP and AQ, cutting PQ at B and C, respectively.
6. Join AB and AC.
Thus, △ABC is the required triangle.
Answered on 01 Jul Learn CBSE/Class 9/Mathematics/Geometry/Quadrilaterals
Answered on 01 Jul Learn CBSE/Class 9/Mathematics/Geometry/Construction
Given: In ∆ABC
AB + BC + CA = 10 cm, ∠B = 60° and ∠C = 45°.
Required: To construct ∆ABC.
Steps of Construction :
1. Draw DE = 10 cm
2. At D, construct ∠EDP = 12 of 60°= 30° and at E, construct ∠DEQ =12 of 45° = 22 12∘
3. Let DP and EQ meet at A.
4. Draw perpendicular bisector of AD to meet DE at B.
5. Draw perpendicular bisector of AE to meet DE at C.
6. Join AB and AC. Thus, ABC is the required triangle.
QUESTIONS: 1.Define profit centre. Ans: Profit Centre is a part of business accountable for costs and revenues. State the objective of Cost Accounting. Ans: Objectives of Cost Accounting The...
QUESTIONS: Define Partnership Deed. Answer: A partnership deed is an agreement among the partners which contains ai! the terms of the Partnership. It generally contains the details about all the...
Name some notable economists who estimated India’s per capita income during the colonial period. Ans: The following economists estimated India’s per capita income during the colonial...
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