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Find the maximum value of (x^4-x^2)/(x^6+2x^3-1).

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Tutor

Apply maxima minima concept separately for f(x) and g(x), you ll get the solution to be 0
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Tutor

The function will not have global maxima as the function value will go to infinity. However, at two different values of x, local maxima having value 1/6 is associated with this function. the corresponding values of x are (1/2 + (root(5))/2), (1/2 - (root(5))/2).
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Tutor

After solving it, you will get that the maxima will occur at (rt5+1)/2 and the maximum value will be 1/6.
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An Engineer

Consider the question to be in the form f(x)/g(x). Now it is very clear it will be maximum only when f(x) is max. and g(x) is minimum. Apply maxima minima concept separately for f(x) and g(x), you ll get the solution to be 0
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0
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Computer Wizard

It's around x = -0.555 which comes around 0.34
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Maths Tutor for the last 15 years - an IIT Engineer with 22 years' experience in the IT Industry

Are you sure there is a minus sign in the denominator?
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perspicacious, physicist, rationalist

for finding maxima u need to do by finding the derivative and look for x which give its minimum value in denominator, And the answer is 0
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NumGeek

zero
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Excellence Award Winner ( 7 times )

it will be 0
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Dear friends, Please correct me in case I am wrong. I your opinion , what should be the maximum number of students in a coaching class, so that each student can have maximum dedicated time from the attending teacher in the classroom. In present days, cost and time of coaching / tuition matters a lot . The same will be demontrated by the following two examples : Example 1 : Suppose a student pays Rs. 4000/= per month ( 26 days in a month , excluding Sundays ), One hour per day , number of student is only one, then cost of coaching per minute works out to (Rs. 4000/=X 1 Student )/(26 days X 60 min/day ) = Rs.2.56 per min. cost and he will get dedicated time of 60 min. each day to carry on his studies. Example - 2 : Suppose a student pays Rs. 2000/= per month ( 26 days in a month , excluding Sundays ), One hour per day , number of student is 30 in a class, then cost of coaching per minute works out to (Rs. 2000/=X 30 Students in a coaching class ) / (26 days X 60 min/day ) = Rs.38.46 per min. cost and he will get dedicated time of only two min. each day for his studies. The above examples shows that though the monthly fees paid by each student is just half ( Rs. 2000/= see example -2 ) in case of classroom type of coaching as compared to the individual coaching ( Rs. 4000/= see example - 1 ), but on the other side cost of coaching per min. based on true dedicated time is 15 times higher in case of classroom type coaching with mass students than single student coaching. These can be however extrapolated for any number of students in a coaching class. As a result the speed of learning process of a student will be about fifteen times slower in classroom type coaching having mass students in a class ignoring the other factors. However, it may be the choice of the students and parents which option is better for them ? Regards, Sudhansu bhushan Roy.
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