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A photon of wavelength 4.0 x m strikes on metal surface, the work function of the metal being 2.13 eV. Calculate:

i. The energy of the photon (eV).

ii. The kinetic energy of the emission.

Iii. The velocity of the photoelectron.

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I) E = hv/wavelength =(6.626*10^-34)(3*10^8)/4*10^-7 = 4.9695*10^-19J ii)K.E=4.9695*10^-19/1.60*10^-19 =3.105eV
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1. 4.97 ×10-19 / 1.602 ×10-19 eV 2. 0.97eV 3. 5084×105 ms-1
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1. 4.97 ×10-19 / 1.602 ×10-19 eV 2. 0.97eV 3. 5084×105 ms-1
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Founder of GRIP Academy (Growing Realm of Intelligence and Perfection)

Energy of photon= hc/λ h=plank constant = 6.63* h*c= 1240 eV λ= wavelength of light E= / J E=3.102 eV 2.)Kinetic energy of emission= energy of photon- work function =3.102-2.13 eV = 0.972 eV 3.) kinetic energy of...
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Energy of photon= hc/λ

h=plank constant = 6.63*

h*c= 1240 eV

λ= wavelength of light

E= / J

E=3.102 eV

2.)Kinetic energy of emission= energy of photon- work function

                                      =3.102-2.13 eV

                                      = 0.972 eV

3.) kinetic energy of electron = 1/2*m* = 0.972 eV

                                                   v=

                                                      =5.84 m/s

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I) E = hv/wavelength =(6.626*10^-34)(3*10^8)/4*10^-7 = 4.969*10^-19 J
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Mathematics and science Home Tutor

Energy of photon= hc/λ h=plank constant = 6.63* c=speed of light=3* h*c= 1240 eV λ= wavelength of light E= / joule E=3.102 eV 2.)Kinetic energy of emission= energy of photon- work function =3.102-2.13 eV ...
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Energy of photon= hc/λ

h=plank constant = 6.63*

c=speed of light=3*

h*c= 1240 eV

λ= wavelength of light

E= / joule

E=3.102 eV

2.)Kinetic energy of emission= energy of photon- work function

                                      =3.102-2.13 eV

                                      = 0.972 eV

3.)Velocity of free Electrons 

kinetic energy of electron = 1/2*m* = 0.972 eV

                                                   v=

                                                      =5.84 m/s

 

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E=hc/wavelength=3.10ev K.E. of photoelectron = (KE of incident photon) - (Work Function of Metal)=3.10-2.13=0.87ev Velocity of photoelctron={2*k.E/m}^{0.5}=30um/sec
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Tutor

(1) Energy of the photon (E) = hν = hc/λ = (6.626×10-34 Js×3.0×108 ms-1)/4×10-7 m = 4.97×10-19 J= 4.97×10-19/1.602×10-19 eV (2) Kinetic energy of emission (1/2 mv2) = hν- hνo = 3.10-2.13 = 0.97 eV (3) 1/2 mv2 = 0.97 eV = 0.97×1.602×10-19...
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(1) Energy of the photon (E) = hν = hc/λ = (6.626×10-34 Js×3.0×10ms-1)/4×10-7 m = 4.97×10-19 J
= 4.97×10-19/1.602×10-19 eV


(2) Kinetic energy of emission (1/2 mv2) = hν- hνo = 3.10-2.13 = 0.97 eV


(3) 1/2 mv= 0.97 eV = 0.97×1.602×10-19 J
⇒ 1/2×(9.11×10-31 kg)×v= 0.97×1.602×10-19 J
⇒ v= 0.341×1012 = 34.1×1010
⇒ v = 5.84×10ms-1

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