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A body of mass 2 kg initially at rest moves under the action of an applied horizontal force of 7 N on a table with coefficient of kinetic friction = 0.1. Compute the (a) Work done by the applied force in 10 s (b) Work done by friction in 10 s (c) Work done by the net force on the body in 10 s (d) Change in kinetic energy of the body in 10 s and interpret your results.

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A-875 joules B-250 joules C-625 joules D-625 joules
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Retired teacher. 30 years experience in physics, chemistry, & biology. MSc biochemistry BEd

Wd by applied force :- 882j Wd by friction:- -246.9j Wd by net force :- 635.04 j Change in ke I equal to wd ,which is equal to 635.04 j.
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