UrbanPro
Login Ask & Answer Success Stories Paid Courses Free Classes Tuition & Classes Fees Write a Review All Categories Help Center
Post your Learning Need Signup as a Tutor
✕

Popular Cities

Bangalore

Hyderabad

Delhi

Mumbai

Chennai

Pune

Kolkata

Gurgaon

Ahmedabad

Jaipur

Noida

✕

Take Class 10 Tuition from the Best Tutors

  • Affordable fees
  • 1-1 or Group class
  • Flexible Timings
  • Verified Tutors

Book a Free Demo

Class 10 > Learn Mathematics > Solve : 55x + 52y = 217; 52x + 55y = 217
✕

Search in

Solve : 55x + 52y = 217; 52x + 55y = 217

Asked by Last Modified  

8 Answers

Learn Mathematics +1 Class IX-X Tuition

Follow 7
Answer

Please enter your answer

subtract two equations from each other, we get x=y and then substitute x=y in any of the equation we get values for x and y . x=1.972 ,y= 1.972
Comments
Dislike Bookmark

Biotechnologist

Firstly, from the first equation, find x. From eqn 1: x = 217 - 52y/55. Now, substitute this value of x in the first eqn. i.e. 52 X (217 - 52y)/55 = 217 Now, multiply both sides with the denominator 55. Therefore, the eqn is 52(217-52y) + 3025y=11935 Solve for y. y = 217/107 ...
read more
Firstly, from the first equation, find x. From eqn 1: x = 217 - 52y/55. Now, substitute this value of x in the first eqn. i.e. 52 X (217 - 52y)/55 = 217 Now, multiply both sides with the denominator 55. Therefore, the eqn is 52(217-52y) + 3025y=11935 Solve for y. y = 217/107 Now, substitute this value of y in the x = 217 - 52y/55 which was derived from the original eqn. Therefore x = 217 - 52(217/107) /55 which is x = 217/107. Therefore, x = y = 217/107 read less
Comments
Dislike Bookmark

Tutor

First of all this is a question of simultaneous equations. But it has a trick under its sleeve. The main thing is to identify that little twist in this question. The RHS of both the equations have the same number. So, if we subtract one equation from the other, we can express x in terms of y. Lets...
read more
First of all this is a question of simultaneous equations. But it has a trick under its sleeve. The main thing is to identify that little twist in this question. The RHS of both the equations have the same number. So, if we subtract one equation from the other, we can express x in terms of y. Lets do it... 55x + 52y - 52x - 55y = 217-217 3x - 3y = 0 x = y. Great!! We got x = y. So substituting x in place of y in 1st equation we can get the value of x. Therefore, 55x + 52x = 217 107x = 217 x = 217/107 = 2.028 Also, y = x So y = 2.028 Therefore, the solution is (2.028,2.028) read less
Comments
Dislike Bookmark

Tutor

X=Y=217/107
Comments
Dislike Bookmark

Trainer

=>55x+52y=217..........................(i) =>52x+55y=217..........................(ii) Adding equation (i) & (ii), We have 77 (x+y)=434 =>x+y=434/77..................(iii) Subtracting (ii) from (i), We have=>x-y=0-----------------------(iv) From equation (iii) & (iv), we have x=217/77 y=217...
Comments
Dislike Bookmark

Tutor

2.02
Comments
Dislike Bookmark

Eco, Maths and Stats Tutor

subtract any one of the equations from another to get x=y. substitute this in any one of the equations to get x=y=2.03
Comments
Dislike Bookmark

As the summation of both eqns are same, we can equate the equations 52x+55y = 55x+52y => 3y=3x ( same eqn can be achieved by subtracting both eqns) => x=y Now putting this in any eqn We get 55x + 52x=217 => 107x=217 => x =y=217/107
Comments
Dislike Bookmark

View 6 more Answers

Related Questions

A triangular park has sides 120 m, 80 m and 50 m. A gardener has to put a fence all around it and also plant grass inside. How much area does he need to plant? Find the cost of fencing it with barbed wire at the rate of Rs. 20 per metre, leaving a space of 3 m wide for a gate on one side.
Perimeter of the garden=120+80+50 =250m As space of 3 m wide for a gate is left on one side, so the length of wire required =(250-3)=247m. Cost of fencing=247X20=Rs 4940. semiperimeter(s)=perimeter/2...
Princy
0 0
5
Show that x = 2 and y = 1 satisfy the linear equation 2x 3y = 7.
2x + 3y=7 Put 2 in place of x and 1 in place of y. 2*2+ 3*1=4+3=7
Sajjan

What are the important topics to cover for ICSE Maths for 9th class students. Also please share any sample blueprints for 2019-2020.
Algebra, e.g. quadratic equations, linear equation, geometry triangle, circle, straight line etc
Rajesh Reddy
0 0
5

What needs to be done to score 100% in maths if my ward is scoring 95% in class IX CBSE?

 
It's not big job if he is getting 95 percent just ask him to do practice as much as he can. Don't put pressure on him to score 100.He will got 100 marks if he will not take any pressure during exam.
V
The mean of 10, 15, x, 5, 15 is 15. What is the value of x?
Mean=sum of all observations÷total no. of observations 15 = (10+15+X+5+15) ÷ 5 75 = 45 + X X = 75 - 45 X = 30 So x is 3
Rayyan
0 0
9

Now ask question in any of the 1000+ Categories, and get Answers from Tutors and Trainers on UrbanPro.com

Ask a Question

Related Lessons

Numbers 2
Whole number can not be a Natural Number because whole number starts from 0 while Natural number starts from 1 which des not includes zero as it not include zero so it can not be a whole number. Natural...

Kanika

1 0
0
Class-9-Maths L-1 Number System Ex1.3 Q1 (iv)-(vi)

Ashish Bhatia

0 0
0
Class-9-Maths L-1 Number System Ex1.3 Q1 (i)-(iii)

Ashish Bhatia

0 0
0
Class-9-Maths L-1 Number System Ex1.1 Q3

Ashish Bhatia

0 0
0
Class-9-Maths L-1 Number System Ex1.5 Q1 (i)-(iii)

Ashish Bhatia

0 0
0

Recommended Articles

Meet Sandhya R, a B.Sc tutor from Bangalore

Sandhya is a proactive educationalist. She conducts classes for CBSE, PUC, ICSE, I.B. and IGCSE. Having a 6-year experience in teaching, she connects with her students and provides tutoring as per their understanding. She mentors her students personally and strives them to achieve their goals with ease. Being an enthusiastic...

Read full article >

Meet Swati, a Hindi Tutor from Bangalore

Swati is a renowned Hindi tutor with 7 years of experience in teaching. She conducts classes for various students ranging from class 6- class 12 and also BA students. Having pursued her education at Madras University where she did her Masters in Hindi, Swati knows her way around students. She believes that each student...

Read full article >

Quest Academy - Institute of the month

Quest Academy is a professional Bangalore based NEET and JEE (Main + Advanced) training institute. The academy was incorporated in 2015 to cater to the needs of students, who aim to crack competitive exams by connecting with the best brains around. The institute helps students enhance their skills and capabilities through...

Read full article >

Meet Mohammad Wazid, a skilled trainer for...

Mohammad Wazid is a certified professional tutor for class 11 students. He has 6 years of teaching experience which he couples with an energetic attitude and a vision of making any subject easy for the students. Over the years he has developed skills with a capability of understanding the requirements of the students. This...

Read full article >

Find Class X Tuition near you
Class X Tuition in Delhi
Class X Tuition in Bangalore
Class X Tuition in Hyderabad
Class X Tuition in Kolkata
Class X Tuition in Mumbai
Class X Tuition in Chennai
Class X Tuition in Pune
Class X Tuition in Noida
Class X Tuition in Lucknow
Class X Tuition in Jaipur
Online Tuition Class 10

Looking for Class 10 Tuition ?

Learn from the Best Tutors on UrbanPro

Are you a Tutor or Training Institute?

Join UrbanPro Today to find students near you
X

Looking for Class 10 Tuition Classes?

The best tutors for Class 10 Tuition Classes are on UrbanPro

  • Select the best Tutor
  • Book & Attend a Free Demo
  • Pay and start Learning

Take Class 10 Tuition with the Best Tutors

The best Tutors for Class 10 Tuition Classes are on UrbanPro

This website uses cookies

We use cookies to improve user experience. Choose what cookies you allow us to use. You can read more about our Cookie Policy in our Privacy Policy

Accept All
Decline All

UrbanPro.com is India's largest network of most trusted tutors and institutes. Over 55 lakh students rely on UrbanPro.com, to fulfill their learning requirements across 1,000+ categories. Using UrbanPro.com, parents, and students can compare multiple Tutors and Institutes and choose the one that best suits their requirements. More than 7.5 lakh verified Tutors and Institutes are helping millions of students every day and growing their tutoring business on UrbanPro.com. Whether you are looking for a tutor to learn mathematics, a German language trainer to brush up your German language skills or an institute to upgrade your IT skills, we have got the best selection of Tutors and Training Institutes for you. Read more

ThinkVidya Learning Pvt Ltd © 2010-2024All Rights Reserved