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Gurukul Education Center Class 11 Tuition institute in Pune

Gurukul Education Center

Dhanori, Pune, India - 411015

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Referral Discount: Get ₹ 250 off when you make a payment to start classes. Get started by Booking a Demo.

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Overview

Our institute is dedicated towards preparing students for competitive exams.
We can teach subjects with ease and make the subject enjoyable for students.

Address

Off. No no. 203, 2nd floor, L square building, survey no. 283, behind Orchid Hopital, Porwal road

Dhanori, Pune, India - 411015

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Teaches

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

At the Institute

Board

State, ISC/ICSE, CBSE

ISC/ICSE Subjects taught

Chemistry, Physics, Mathematics

CBSE Subjects taught

Chemistry, Mathematics, Physics

State Syllabus Subjects taught

Mathematics, Physics, Chemistry

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

At the Institute

Board

State, ISC/ICSE, CBSE

ISC/ICSE Subjects taught

Chemistry, Physics, Mathematics

CBSE Subjects taught

Chemistry, Mathematics, Physics

State Syllabus Subjects taught

Mathematics, Physics, Chemistry

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

At the Institute

Board

State, ICSE, CBSE

CBSE Subjects taught

Science, Mathematics

ICSE Subjects taught

Chemistry, Physics, Mathematics, Biology

State Syllabus Subjects taught

Science, Mathematics

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

At the Institute

Board

State, ICSE, CBSE

CBSE Subjects taught

Science, Mathematics

ICSE Subjects taught

Chemistry, Physics, Mathematics, Biology

State Syllabus Subjects taught

Science, Mathematics

Engineering Entrance Coaching classes

Class Location

Online (video chat via skype, google hangout etc)

At the Institute

Engineering Entrance Exams

IIT JEE Coaching Classes

Type of class

Regular Classes

IIT JEE Coaching

IIT JEE Mains Coaching, IIT JEE Advanced Coaching, IIT JEE Foundation Course

IIT-JEE Subjects

Maths, Chemistry , Physics

Courses

Crash course
LIVE
2 Hours
View this Course

Reviews

No Reviews yet!

FAQs

1. Which school boards of of Class 11 do you teach for?

State, ISC/ICSE, CBSE

2. Which classes do you teach?

We teach Class 10 Tuition, Class 11 Tuition, Class 12 Tuition, Class 9 Tuition and Engineering Entrance Coaching Classes

3. Do you provide a demo class?

Yes, We provide a free demo class.

4. Where are you located?

We are located in Dhanori, Pune.

Contact

Answers by Gurukul Education Center (23)

Answered on 24/12/2017 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

The perimeter of one face of a wooden cube is 20 cm. Find its weight if 1 cm3 of wood weighs 8.25 g.

Perimeter of a cube with side a = 12 *a = 20cm Therefore , a = 5/3 cm Now , volume of cube = a^3 = (5/3)^3 = 125/27 cm3 If weight of 1cm3 is 8.25g Then weight of 125/27 cm3 will be = 8.25 * 125/27 gm = 38.19gm (ans)
Answers 5 Comments
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Answered on 10/12/2017 Learn CBSE/Class 9/Mathematics +1 Tuition/Class IX-X Tuition

Factorise: 14x6 – 45x3y3 – 14y6

14x6 - 45x3y3-14y6 = 14x6-49x3y3+4x3y3-14y6 = 7x3 (2x3-7y3)+2y3(2x3-7y3) = (7x3+2y3)(2x3-7y3)
Answers 11 Comments
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Answered on 10/12/2017 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

If the numbers a, b, c, d and e form an A.P., then find the value of a – 4b + 6c – 4d + e.

Let a = A-2D b = A-D c = A d = A+D e = A+2D a-4b+6c-4d+e = A-2D-4(A-D)+6A-4(A+D)+A+2D = 0
Answers 11 Comments
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Answered on 10/12/2017 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

Had Ravita scored 10 more marks in her Mathematics test out of 30 marks, 9 times these marks would have... ...more
Had Ravita scored 10 more marks in her Mathematics test out of 30 marks, 9 times these marks would have been the square of her actual marks. How many marks did she get in the test?

Let the marks scored in Mathematics be x. As given, 9( x+10 ) = x2 x2-9x-90 = 0 x2-15x+6x-90 =0 x(x-15)+6(x-15) = 0 (x+6)(x-15) = 0 Therefore, x = 15 ( x = -6 is ignored)
Answers 6 Comments
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Answered on 10/12/2017 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

A motor boat whose speed is 18 km/h in still water takes 1 hour more to go 24 km upstream than to return... ...more
A motor boat whose speed is 18 km/h in still water takes 1 hour more to go 24 km upstream than to return downstream to the same spot. Find the speed of the stream.

Let the speed of stream by x kmph. then speed of boat in water upstream = (18-x) kmph Speed of boat in water downstream = (18+x) kmph Now time = Distance / speed Time taken to go upstream - time taken to go downstream = 1 hr 24/(18-x) - 24/(18+x) = 1 24( 18+x-18+x ) = (18^2 - x2) 48x = 324... ...more
Let the speed of stream by x kmph. then speed of boat in water upstream = (18-x) kmph Speed of boat in water downstream = (18+x) kmph Now time = Distance / speed Time taken to go upstream - time taken to go downstream = 1 hr 24/(18-x) - 24/(18+x) = 1 24( 18+x-18+x ) = (18^2 - x2) 48x = 324 - x2 x2+48x-324 = 0 x2+54x-6x-324 = 0 x(x+54)-6(x+54) = 0 (x-6)(x+54) = 0 therefore, speed of stream (x) = 6kmph
Answers 5 Comments
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Contact

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Teaches

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

At the Institute

Board

State, ISC/ICSE, CBSE

ISC/ICSE Subjects taught

Chemistry, Physics, Mathematics

CBSE Subjects taught

Chemistry, Mathematics, Physics

State Syllabus Subjects taught

Mathematics, Physics, Chemistry

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

At the Institute

Board

State, ISC/ICSE, CBSE

ISC/ICSE Subjects taught

Chemistry, Physics, Mathematics

CBSE Subjects taught

Chemistry, Mathematics, Physics

State Syllabus Subjects taught

Mathematics, Physics, Chemistry

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

At the Institute

Board

State, ICSE, CBSE

CBSE Subjects taught

Science, Mathematics

ICSE Subjects taught

Chemistry, Physics, Mathematics, Biology

State Syllabus Subjects taught

Science, Mathematics

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

At the Institute

Board

State, ICSE, CBSE

CBSE Subjects taught

Science, Mathematics

ICSE Subjects taught

Chemistry, Physics, Mathematics, Biology

State Syllabus Subjects taught

Science, Mathematics

Engineering Entrance Coaching classes

Class Location

Online (video chat via skype, google hangout etc)

At the Institute

Engineering Entrance Exams

IIT JEE Coaching Classes

Type of class

Regular Classes

IIT JEE Coaching

IIT JEE Mains Coaching, IIT JEE Advanced Coaching, IIT JEE Foundation Course

IIT-JEE Subjects

Maths, Chemistry , Physics

Courses

Crash course
LIVE
2 Hours
View this Course
No Reviews yet!

Answers by Gurukul Education Center (23)

Answered on 24/12/2017 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

The perimeter of one face of a wooden cube is 20 cm. Find its weight if 1 cm3 of wood weighs 8.25 g.

Perimeter of a cube with side a = 12 *a = 20cm Therefore , a = 5/3 cm Now , volume of cube = a^3 = (5/3)^3 = 125/27 cm3 If weight of 1cm3 is 8.25g Then weight of 125/27 cm3 will be = 8.25 * 125/27 gm = 38.19gm (ans)
Answers 5 Comments
Dislike Bookmark

Answered on 10/12/2017 Learn CBSE/Class 9/Mathematics +1 Tuition/Class IX-X Tuition

Factorise: 14x6 – 45x3y3 – 14y6

14x6 - 45x3y3-14y6 = 14x6-49x3y3+4x3y3-14y6 = 7x3 (2x3-7y3)+2y3(2x3-7y3) = (7x3+2y3)(2x3-7y3)
Answers 11 Comments
Dislike Bookmark

Answered on 10/12/2017 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

If the numbers a, b, c, d and e form an A.P., then find the value of a – 4b + 6c – 4d + e.

Let a = A-2D b = A-D c = A d = A+D e = A+2D a-4b+6c-4d+e = A-2D-4(A-D)+6A-4(A+D)+A+2D = 0
Answers 11 Comments
Dislike Bookmark

Answered on 10/12/2017 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

Had Ravita scored 10 more marks in her Mathematics test out of 30 marks, 9 times these marks would have... ...more
Had Ravita scored 10 more marks in her Mathematics test out of 30 marks, 9 times these marks would have been the square of her actual marks. How many marks did she get in the test?

Let the marks scored in Mathematics be x. As given, 9( x+10 ) = x2 x2-9x-90 = 0 x2-15x+6x-90 =0 x(x-15)+6(x-15) = 0 (x+6)(x-15) = 0 Therefore, x = 15 ( x = -6 is ignored)
Answers 6 Comments
Dislike Bookmark

Answered on 10/12/2017 Learn CBSE/Class 10/Mathematics +1 Tuition/Class IX-X Tuition

A motor boat whose speed is 18 km/h in still water takes 1 hour more to go 24 km upstream than to return... ...more
A motor boat whose speed is 18 km/h in still water takes 1 hour more to go 24 km upstream than to return downstream to the same spot. Find the speed of the stream.

Let the speed of stream by x kmph. then speed of boat in water upstream = (18-x) kmph Speed of boat in water downstream = (18+x) kmph Now time = Distance / speed Time taken to go upstream - time taken to go downstream = 1 hr 24/(18-x) - 24/(18+x) = 1 24( 18+x-18+x ) = (18^2 - x2) 48x = 324... ...more
Let the speed of stream by x kmph. then speed of boat in water upstream = (18-x) kmph Speed of boat in water downstream = (18+x) kmph Now time = Distance / speed Time taken to go upstream - time taken to go downstream = 1 hr 24/(18-x) - 24/(18+x) = 1 24( 18+x-18+x ) = (18^2 - x2) 48x = 324 - x2 x2+48x-324 = 0 x2+54x-6x-324 = 0 x(x+54)-6(x+54) = 0 (x-6)(x+54) = 0 therefore, speed of stream (x) = 6kmph
Answers 5 Comments
Dislike Bookmark

Contact

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Gurukul Education Center conducts classes in Class 10 Tuition, Class 11 Tuition and Class 12 Tuition. It is located in Dhanori, Pune. It takes Regular Classes- at the Institute.

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