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A traffic signal board, indicating ‘SCHOOL AHEAD’, is an equilateral triangle with side ‘a’. Find the area of the signal board, using Heron’s formula. If its perimeter is 180 cm, what will be the area of the signal board?

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The perimeter of a triangle is equal to the sumof its three sides it is denoted by 2S.2s=(a+b+c)s=(a+b+c)/2Here ,s is called semi perimeter of a triangle. The formula given by Heron about the area of atriangle is known as Heron's formula. According to this formula area of atriangle= √s (s-a) (s-b)...
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The perimeter of a triangle is equal to the sum
of its three sides it is denoted by 2S.
2s=(a+b+c)
s=(a+b+c)/2
Here ,s is called semi perimeter of a triangle.
 
The formula given by Heron about the area of a
triangle is known as Heron's formula. According to this formula area of a
triangle= √s (s-a) (s-b) (s-c)
Where a, b and c are three sides of a triangle
and s is a semi perimeter.
 
This formula can be used for any triangle to
calculate its area and it is very useful when it is not possible to find the height
of the triangle easily . Heron's formula is
generally used for calculating area of scalene triangle.
____________________________________________________________
 Solution:Given, side of a signal whose shape is an equilateral triangle= a
Semi perimeter, s=a+a+a/2= 3a/2
Using heron’s formula,
Area of the signal board = √s (s-a) (s-b) (s-c)= √(3a/2) (3a/2 – a) (3a/2 – a) (3a/2 – a)
= √3a/2 × a/2 × a/2 × a/2
= √3aâ?´/16
= √3a²/4
Hence, area of signal board with side a by using Herons formula is= √3a²/4
Now,Perimeter of an equilateral triangle= 3a
Perimeter of the traffic signal board = 180 cm 
(given) 3a = 180 cm a = 180/3= 60 cm
Now , area of signal board=√3a²/4
= √3/4 × 60 × 60 = 900√3 cm²
Hence , the area of the signal board when perimeter is 180 cm is 900√3 cm².
 

 

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Perimeter of the board = 180cm ∴ 3a = 180cm ∴ a = 60cm. Area of the board = √3/4a² = √3/4 × 60×60 = √3 ×15 × 60 = √900√3 cm².
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Maths Teacher for classes 6th to 10th with 6 years experience and having my own YouTube Channel for clearing doubts

Equilateral triangle of side 'a'. So, s=(a+a+a)/2=3a/2. So, Area of the triangle =√(3a/2) (3a/2 - a) (3a/2 - a) (3a/2 - a) = √(3a/2) (a/2) (a/2) (a/2) = (a²√3)/4. Now, perimeter of the signal board = 180cm. Since, it is an equilateral triangle, each side will be 60cm. So, here...
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Equilateral triangle of side 'a'.

So, s=(a+a+a)/2=3a/2.

So, Area of the triangle =√(3a/2) (3a/2 - a) (3a/2 - a) (3a/2 - a) = √(3a/2) (a/2) (a/2) (a/2) = (a²√3)/4.

Now, perimeter of the signal board = 180cm. Since, it is an equilateral triangle, each side will be 60cm. So, here a = 60cm and the area of the signal board can be found out by substituting the value of a = 60cm in the formula (a²√3)/4. So, it becomes, (60²√3)/4 = 1558.85cm² 

                                

 

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Given parameter =180 cm i.e. 3a=180cm a=60cm S= perimeter /2 =90 cm Heron formula is- Area= ^1/2 Where a ,b,c = side of the triangle Here given triangle is equilateral Therefore a=b= c= 60cm Now, Area=^1/2 = ^1/2 = ^1/2 = ^1/2=90cm sq. Therefore are of the sign board =90cm...
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Given parameter =180 cm 

i.e. 3a=180cm 

a=60cm

S= perimeter /2 =90 cm 

Heron formula is-

Area= [S{(S-a)+(S-b)+(S-c)}]^1/2 

Where a ,b,c = side of the triangle

Here given triangle is equilateral 

Therefore 

a=b= c= 60cm

Now,

Area=[90{(90-60)+(90-60)+(90-60)}]^1/2

        = [90{30+30+30}]^1/2

        = [90×90]^1/2

        = [90^2]^1/2=90cm sq.

Therefore are of the sign board =90cm sq 

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I never got rejected after a demo class in my 4 yrs teaching exeperience. Thats it!

Perimeter =180 so each side =60,then semi perimeter =90; now by heron's formula = (90-60)(90-60)(90-60)=*30*30*30 =3*3*100root3=900root3 squarecm
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Perimeter =180 so each side =60,then semi perimeter =90;

now by heron's formula = (90-60)(90-60)(90-60)=*30*30*30

=3*3*100root3=900root3 squarecm

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Comments

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