Bindapur Jivan Park, Delhi, India - 110059.
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Hindi Mother Tongue (Native)
English Proficient
University of delhi 2017
BSc. Mathematics
Bindapur Jivan Park, Delhi, India - 110059
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1 Student Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
4
Board
ICSE, CBSE, State
CBSE Subjects taught
English, Social science, Mathematics, Science
ICSE Subjects taught
Physics, Economics, Mathematics, History and Civics, Chemistry, Biology, Geography
Taught in School or College
No
State Syllabus Subjects taught
Science, English, Mathematics, Social Science
1. Which school boards of Class 10 do you teach for?
ICSE, CBSE and State
2. Do you have any prior teaching experience?
No
3. Which classes do you teach?
I teach Class 10 Tuition Class.
4. Do you provide a demo class?
Yes, I provide a free demo class.
5. How many years of experience do you have?
I have been teaching for 4 years.
Answered on 07/08/2019 Learn CBSE/Class 9/Mathematics/Mensuration/Heron's formula/NCERT Solutions/Exercise 12.1
Given parameter =180 cm
i.e. 3a=180cm
a=60cm
S= perimeter /2 =90 cm
Heron formula is-
Area= [S{(S-a)+(S-b)+(S-c)}]^1/2
Where a ,b,c = side of the triangle
Here given triangle is equilateral
Therefore
a=b= c= 60cm
Now,
Area=[90{(90-60)+(90-60)+(90-60)}]^1/2
= [90{30+30+30}]^1/2
= [90×90]^1/2
= [90^2]^1/2=90cm sq.
Therefore are of the sign board =90cm sq
1 Student Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
4
Board
ICSE, CBSE, State
CBSE Subjects taught
English, Social science, Mathematics, Science
ICSE Subjects taught
Physics, Economics, Mathematics, History and Civics, Chemistry, Biology, Geography
Taught in School or College
No
State Syllabus Subjects taught
Science, English, Mathematics, Social Science
Answered on 07/08/2019 Learn CBSE/Class 9/Mathematics/Mensuration/Heron's formula/NCERT Solutions/Exercise 12.1
Given parameter =180 cm
i.e. 3a=180cm
a=60cm
S= perimeter /2 =90 cm
Heron formula is-
Area= [S{(S-a)+(S-b)+(S-c)}]^1/2
Where a ,b,c = side of the triangle
Here given triangle is equilateral
Therefore
a=b= c= 60cm
Now,
Area=[90{(90-60)+(90-60)+(90-60)}]^1/2
= [90{30+30+30}]^1/2
= [90×90]^1/2
= [90^2]^1/2=90cm sq.
Therefore are of the sign board =90cm sq
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