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Asked by Fgrefg Last Modified
Answer Let the breadth be x m. The length will be (2x + 2) m.
Perimeter of swimming pool = 2(l + b) = 154 m
2(2x + 2 + x) = 154
2(3x + 2) = 154
Dividing both sides by 2, we obtain
3x + 2 = 77
On transposing 2 to R.H.S, we obtain
3x = 77 − 2
3x = 75
On dividing both sides by 3, we obtain
x = 25
2x + 2 = 2 × 25 + 2 = 52
Hence, the breadth and length of the pool are 25 m and 52 m respectively.
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Let l,b are the length and breadth of pool respectively.
l=2b+2...............(1)
perimeter=2(l+b)=154.............(2)
from (2)
l+b = 154/2=77..............(3)
substituting (1) in (3)
2b+2+b=77
3b=77-2=75
b=75/3=25
l=2b+2=2*25+2=50+2=52
length=52 m
breadth=25 m
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