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Asked by Rahul Last Modified
Answer Here, some cuboids of size 5 × 2 × 5 are given.
When these cuboids are arranged to form a cube, the side of this cube so formed will be a common multiple of the sides (i.e., 5, 2, and 5) of the given cuboid.
LCM of 5, 2, and 5 = 10
Let us try to make a cube of 10 cm side.
For this arrangement, we have to put 2 cuboids along with its length, 5 along with its width, and 2 along with its height.
Total cuboids required according to this arrangement = 2 × 5 × 2 = 20
With the help of 20 cuboids of such measures, a cube is formed as follows.
Alternatively
Volume of the cube of sides 5 cm, 2 cm, 5 cm
= 5 cm × 2 cm × 5 cm = (5 × 5 × 2) cm3
Here, two 5s and one 2 are left which are not in a triplet.
If we multiply this expression by 2 × 2 × 5 = 20, then it will become a perfect cube.
Thus, (5 × 5 × 2 × 2 × 2 × 5) = (5 × 5 × 5 × 2 × 2 × 2) = 1000 is a perfect cube. Hence, 20 cuboids of 5 cm, 2 cm, 5 cm are required to form a cube.
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