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Asked by Rishav Last Modified
Answer 
Assume the 2 digit number as xy, where x and y are first and second digits respectively.
x=3y..............(1)
new number after interchanging digits is yx.
xy+yx=88
that means
10x+y+10y+x=88
11x+11y=88
11(x+y)=88
x+y=88/11=8..............(2)
substituting (1) in (2)
3y+y=8
4y=8
y=8/4
y=2
x=3y=3*2=6
original number=xy=62
read lessLet the digits at tens place and ones place be x and 3x respectively.
Therefore, original number = 10x + 3x = 13x
On interchanging the digits, the digits at ones place and tens place will be x and 3x respectively.
Number after interchanging = 10 × 3x + x = 30x + x = 31x
According to the given question,
Original number + New number = 88
13x + 31x = 88
44x = 88
Dividing both sides by 44, we obtain
x = 2
Therefore, original number = 13x = 13 × 2 = 26
By considering the tens place and ones place as 3x and x respectively, the two-digit number obtained is 62.
Therefore, the two-digit number may be 26 or 62.
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