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Asked by Madhu Last Modified
Answer 
Let Baichung's, his father's, his grandfather's ages are x,y, and z respectively.
z=y+26............(1)
y=x+29..................(2)
substitute (2) in (1)
z=y+26=x+29+26=x+55.............(3)
x+y+z=135............(4)
replace the values of y and z with (1) and (3) in (4)
x+y+z=135
x+x+29+x+55=135
3x+84=135
3x=51
x=51/3=17
y=x+29=17+29=46
z=x+55=72
so the ages are 17,46 and 72 respectively
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Let Baichung’s father’s age be x years. Therefore, Baichung’s age and Baichung’s grandfather’s age will be (x − 29) years and (x + 26) years respectively.
According to the given question, the sum of the ages of these 3 people is 135 years.
∴ x + x − 29 + x + 26 = 135
3x − 3 = 135
On transposing 3 to R.H.S, we obtain
3x = 135 + 3
3x = 138
On dividing both sides by 3, we obtain
x = 46
Baichung’s father’s age = x years = 46 years
Baichung’s age = (x − 29) years = (46 − 29) years = 17 years
Baichung’s grandfather’s age = (x + 26) years = (46 + 26) years = 72 years
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