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Asked by Nabodit Last Modified
Answer 
wheatstone bridge principle.
here p/q=r/s.p=unknown resistance,q=resistance of the resistance box given to the circuit.if l=length of the slide wire at which when tip of the jockey touches it gives zero deflection in the galvanometer,then r=l and s=100-l.
so p=q(l/100-l).
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