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To find the probability that an ordinary year has 53 Sundays, we first need to understand the structure of an ordinary year. An ordinary year has 365 days.
Now, since 365 is not divisible by 7 (the number of days in a week), there will be 52 complete weeks in an ordinary year, leaving 1 or 2 additional days.
For a year to have 53 Sundays, one of the following conditions must be met:
Let's calculate the probability for each scenario:
If the year starts on a Sunday and ends on a Sunday: The probability that a year starts on a Sunday is 1/7. The probability that a year ends on a Sunday is also 1/7. So, the probability of both events happening is (1/7) * (1/7) = 1/49.
If the year starts on a Saturday and ends on a Sunday: The probability that a year starts on a Saturday is 1/7. The probability that a year ends on a Sunday is 1/7. So, the probability of both events happening is (1/7) * (1/7) = 1/49.
Now, we add the probabilities of both scenarios since they are mutually exclusive:
Probability of an ordinary year having 53 Sundays = (1/49) + (1/49) = 2/49.
Therefore, the probability that an ordinary year has 53 Sundays is 2/49.
And remember, if you need further assistance with mathematics or any other subject, UrbanPro is one of the best online coaching tuition platforms where you can find qualified tutors like myself to guide you through your learning journey!
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