UrbanPro

Take Class 11 Tuition from the Best Tutors

  • Affordable fees
  • 1-1 or Group class
  • Flexible Timings
  • Verified Tutors

Search in

The-electrical resistance in ohms of a certain thermometer varies with temperature according to the approximate law: R = R0 [1 + α (T – T0)].The resistances is 101.6 Ωat the triple-point of water 273.16 K, and 165.5 Ωat the normal melting point of lead (600.5 K). What is the temperature when the resistance is 123.4 Ω ?

Asked by Last Modified  

Follow 1
Answer

Please enter your answer

As an experienced tutor registered on UrbanPro, I'd be happy to assist you with this problem. UrbanPro is known for connecting students with expert tutors for personalized learning experiences. For this problem, we're dealing with the relationship between electrical resistance and temperature, which...
read more

As an experienced tutor registered on UrbanPro, I'd be happy to assist you with this problem. UrbanPro is known for connecting students with expert tutors for personalized learning experiences.

For this problem, we're dealing with the relationship between electrical resistance and temperature, which is given by the formula:

R=R0[1+α(T−T0)]R=R0[1+α(TT0)]

where:

  • RR is the resistance at the given temperature TT,
  • R0R0 is the resistance at a reference temperature T0T0,
  • αα is the temperature coefficient of resistance, and
  • TT is the temperature.

Given that the resistance at the triple point of water (T0=273.16 KT0=273.16K) is R0=101.6 ΩR0=101.6Ω and the resistance at the normal melting point of lead (T=600.5 KT=600.5K) is R=165.5 ΩR=165.5Ω, we can use these values to find the value of αα.

First, let's rearrange the equation to solve for αα:

α=R−R0R0(T−T0)α=R0(TT0)RR0

Substituting the given values:

α=165.5−101.6101.6×(600.5−273.16)α=101.6×(600.5−273.16)165.5−101.6

Now, we can find the value of αα.

Once we have αα, we can use it to find the temperature TT when the resistance is R=123.4 ΩR=123.4Ω. Rearranging the equation, we get:

T=T0+R−R0αR0T=T0+αR0RR0

Substitute the given values into this equation to find the temperature corresponding to the resistance of 123.4 Ω123.4Ω.

 
 
read less
Comments

Now ask question in any of the 1000+ Categories, and get Answers from Tutors and Trainers on UrbanPro.com

Ask a Question

Recommended Articles

With the current trend of the world going digital, electronic renaissance is a new movement that is welcomed by the new generation as it helps makes the lives of millions of people easier and convenient. Along with this rapidly changing movement and gaining popularity of Internet, e-Learning is a new tool that emerging...

Read full article >

Once over with the tenth board exams, a heavy percentage of students remain confused between the three academic streams they have to choose from - science, arts or commerce. Some are confident enough to take a call on this much in advance. But there is no worry if as a student you take time to make choice between - science,...

Read full article >

Quality education does not only help children to get a successful career and life, but it also hugely contributes to society. The formal education of every child starts from school. Although there are numerous schools, parents find it challenging to choose the right one that would fit their child. It is difficult for them...

Read full article >

Learning for every child starts from a very young age. While the formal methods include school curriculums and private lessons, the informal methods include dancing, music, drawing, and various fun-filling activities. Playing games and practising these types of activities helps the children get out of boredom and...

Read full article >

Looking for Class 11 Tuition ?

Learn from the Best Tutors on UrbanPro

Are you a Tutor or Training Institute?

Join UrbanPro Today to find students near you
X

Looking for Class 11 Tuition Classes?

The best tutors for Class 11 Tuition Classes are on UrbanPro

  • Select the best Tutor
  • Book & Attend a Free Demo
  • Pay and start Learning

Take Class 11 Tuition with the Best Tutors

The best Tutors for Class 11 Tuition Classes are on UrbanPro

This website uses cookies

We use cookies to improve user experience. Choose what cookies you allow us to use. You can read more about our Cookie Policy in our Privacy Policy

Accept All
Decline All

UrbanPro.com is India's largest network of most trusted tutors and institutes. Over 55 lakh students rely on UrbanPro.com, to fulfill their learning requirements across 1,000+ categories. Using UrbanPro.com, parents, and students can compare multiple Tutors and Institutes and choose the one that best suits their requirements. More than 7.5 lakh verified Tutors and Institutes are helping millions of students every day and growing their tutoring business on UrbanPro.com. Whether you are looking for a tutor to learn mathematics, a German language trainer to brush up your German language skills or an institute to upgrade your IT skills, we have got the best selection of Tutors and Training Institutes for you. Read more