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Asked by Shankar Last Modified
Answer 
If a thermometer is wrong calibrated then,
If X is the temperature reading on the faulty thermometer scale then,
t =(X-LFP)/(UFP-LFP) × 100 . t= actual reading
Now UFP=99°C
LFP= 5°C
X= 52°C
t= 50°C= 122°F
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