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Overview

I am teaching Mathematics and Science in Chrysalis High Bangalore. I am M.Sc. 1st Class in Physics from Presidency College Kolkata. I achieved AIR of 233 in GATE 2013. I have 5 years of experience in home tuition. I also taught Physics in Engineering College for 1 semester. I believe in growing students interest in the subject. Also due to my multiple experiences i am well versed in teaching different types of students. I can change me style according to students need.

Languages Spoken

Bengali

Hindi

English Proficient

Education

Calcutta University 2011

Master of Science (M.Sc.)

Address

Whitefield, Bangalore, India - 560066

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Teaches

Class 6 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 6 Tuition

5

Board

CBSE, ICSE

CBSE Subjects taught

Mathematics, Science

ICSE Subjects taught

Mathematics, Chemistry, Biology, Physics

Taught in School or College

Yes

Class 7 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 7 Tuition

5

Board

CBSE, ICSE

CBSE Subjects taught

Mathematics, Science

ICSE Subjects taught

Mathematics, Chemistry, Biology, Physics

Taught in School or College

Yes

Class 8 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

5

Board

CBSE, ICSE

CBSE Subjects taught

Mathematics, Science

ICSE Subjects taught

Mathematics, Chemistry, Biology, Physics

Taught in School or College

Yes

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

5

Board

CBSE, ICSE

CBSE Subjects taught

Science, Mathematics

ICSE Subjects taught

Physics, Chemistry, Mathematics

Taught in School or College

Yes

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

5

Board

CBSE, ICSE

CBSE Subjects taught

Science, Mathematics

ICSE Subjects taught

Physics, Chemistry, Mathematics

Taught in School or College

Yes

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

5

Board

ISC/ICSE, CBSE

ISC/ICSE Subjects taught

Physics

CBSE Subjects taught

Physics

Taught in School or College

Yes

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

5

Board

ISC/ICSE, CBSE

ISC/ICSE Subjects taught

Physics

CBSE Subjects taught

Physics

Taught in School or College

Yes

Class I-V Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class I-V Tuition

5

Board

CBSE, ICSE

CBSE Subjects taught

Mathematics, Science

ICSE Subjects taught

Mathematics, Science

Taught in School or College

Yes

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 8 do you teach for?

CBSE, ICSE

2. Have you ever taught in any School or College?

Yes

3. Which classes do you teach?

I teach Class 10 Tuition, Class 11 Tuition, Class 12 Tuition, Class 6 Tuition, Class 7 Tuition, Class 8 Tuition, Class 9 Tuition and Class I-V Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 5 years.

Answers by Moumita D. (6)

Answered on 14/10/2018 Learn CBSE/Class 11/Science/Physics

A conservative force is a force with the property that the work done in moving a particle between two points is independent of the taken path. A conservative force is dependent only on the position of the object. To put it another way, the work done depends only on the initial and final position of... ...more

A conservative force is a force with the property that the work done in moving a particle between two points is independent of the taken path. A conservative force is dependent only on the position of the object.

To put it another way, the work done depends only on the initial and final position of the particle.

Suppose we throw a object of mass ‘m’ upward suppose it goes up to a height h.

then the work done in throwing object in upward direction w1 = -mgh (use ‘-g’ sign convention )

and the work done while returning to the same path w2 = mgh

total work done W = w1 + w2 = -mgh+mgh = 0

Hence, total energy loss will also be zero in this case.Hence the total workdone in travelling a certain height and falling back to tha same place is zero. This is the property of coservative force as the total workdone depends only on the initial and final positions of the objects. So, Gravitational Force is Conservative Force.

Answers 2 Comments
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Answered on 11/10/2018 Learn CBSE/Class 11/Science/Physics

Assuming the pond has vertical banks and a non-porous bottom and sides (so we need not worry about drainage and such) then the pond level will be increased when we put the boat in the water . A heavier boat will displace more water. When we remove the rock from the boat the boat will displace less water... ...more

Assuming the pond has vertical banks and a non-porous bottom and sides (so we need not worry about drainage and such) then the pond level will be increased when we put the boat in the water . A heavier boat will displace more water. When we remove the rock from the boat the boat will displace less water and the pond  level will decrease.

Answers 2 Comments
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Answered on 01/10/2018 Learn CBSE/Class 11/Science/Physics

Newton’s Law of Cooling states that the rate of change of temperature of a body is proportional to the difference between the temperature of the body and that of the surrounding medium. It is a reasonably accurate approximation in some circumstances. More precisely, let T denote the temperature... ...more

Newton’s Law of Cooling states that the rate of change of temperature of a body is proportional to the difference between the temperature of the body and that of the surrounding medium. It is a reasonably accurate approximation in some circumstances.

More precisely, let T denote the temperature of an object and Tο the ambient temperature.   if t denotes time, then Newton's law states that

dT/dt  = -k(T-Tο)

where k is a positive constant. Thus, if the object temperature is much higher than its surroundings, then  T-Tο is large and positive, so dTdT/dt is large and negative, so the object cools quickly. If the object temperature is only slightly higher than its surroundings, then T-Tο is small positive, and the object cools slowly. So a cup of coffee will cool more quickly if you put it in the refrigerator! 

 

Answers 3 Comments
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Answered on 01/10/2018 Learn CBSE/Class 11/Science/Physics

Newton’s Law of Cooling states that the rate of temperature of the body is proportional to the difference between the temperature of the body and that of the surrounding medium. It is a reasonably accurate approximation in some circumstances. More precisely, let T denote the temperature of an object... ...more

Newton’s Law of Cooling states that the rate of temperature of the body is proportional to the difference between the temperature of the body and that of the surrounding medium. It is a reasonably accurate approximation in some circumstances.

More precisely, let T denote the temperature of an object and Tο the ambient temperature.   if t denotes time, then Newton's law states that

dT/dt  = -k(T-Tο)

where k is a positive constant. Thus, if the object temperature is much higher than its surroundings, then  T-Tο is large and positive, so dTdT/dt is large and negative, so the object cools quickly. If the object temperature is only slightly higher than its surroundings, then T-Tο is small positive, and the object cools slowly. So a cup of coffee will cool more quickly if you put it in the refrigerator! 

 

Answers 3 Comments
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Answered on 30/09/2018 Learn CBSE/Class 11/Science/Physics

mass=1000kg u=0km/hr=0m/s v=54km/hr=15m/s work= change in kinetic energy = 1/2xmxv^2 - 1/2xmxu^2 = 1/2x1000x15^2 - 0 =112500 J power = work/time = 112500/5 = 22500 J/s=22.5 kw from first eqution of motion v=u+at u=0 therfore v=at 15=5a a=3m/s^2 from second equation of motion s=ut+/2at^2 0+1/2*3*5*% s=37.5... ...more

mass=1000kg 
u=0km/hr=0m/s 
v=54km/hr=15m/s 
work= change in kinetic energy 
= 1/2xmxv^2 - 1/2xmxu^2 
= 1/2x1000x15^2 - 0 
=112500 J 
power = work/time 
= 112500/5 = 22500 J/s=22.5 kw

 

from first eqution of motion

v=u+at

u=0

therfore

v=at

15=5a

a=3m/s^2

 

from second equation of motion 

s=ut+/2at^2

0+1/2*3*5*%

s=37.5 m

now v avg=dsance/time=37.5/5=7.5 m/s

 

gaain in KE=KE fina=KE initial

=1/2mv^2-1/2mv2^2

=1/2*1000*15^=112.5kj

 

Answers 2 Comments
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Teaches

Class 6 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 6 Tuition

5

Board

CBSE, ICSE

CBSE Subjects taught

Mathematics, Science

ICSE Subjects taught

Mathematics, Chemistry, Biology, Physics

Taught in School or College

Yes

Class 7 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 7 Tuition

5

Board

CBSE, ICSE

CBSE Subjects taught

Mathematics, Science

ICSE Subjects taught

Mathematics, Chemistry, Biology, Physics

Taught in School or College

Yes

Class 8 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

5

Board

CBSE, ICSE

CBSE Subjects taught

Mathematics, Science

ICSE Subjects taught

Mathematics, Chemistry, Biology, Physics

Taught in School or College

Yes

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

5

Board

CBSE, ICSE

CBSE Subjects taught

Science, Mathematics

ICSE Subjects taught

Physics, Chemistry, Mathematics

Taught in School or College

Yes

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

5

Board

CBSE, ICSE

CBSE Subjects taught

Science, Mathematics

ICSE Subjects taught

Physics, Chemistry, Mathematics

Taught in School or College

Yes

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

5

Board

ISC/ICSE, CBSE

ISC/ICSE Subjects taught

Physics

CBSE Subjects taught

Physics

Taught in School or College

Yes

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

5

Board

ISC/ICSE, CBSE

ISC/ICSE Subjects taught

Physics

CBSE Subjects taught

Physics

Taught in School or College

Yes

Class I-V Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class I-V Tuition

5

Board

CBSE, ICSE

CBSE Subjects taught

Mathematics, Science

ICSE Subjects taught

Mathematics, Science

Taught in School or College

Yes

No Reviews yet!

Answers by Moumita D. (6)

Answered on 14/10/2018 Learn CBSE/Class 11/Science/Physics

A conservative force is a force with the property that the work done in moving a particle between two points is independent of the taken path. A conservative force is dependent only on the position of the object. To put it another way, the work done depends only on the initial and final position of... ...more

A conservative force is a force with the property that the work done in moving a particle between two points is independent of the taken path. A conservative force is dependent only on the position of the object.

To put it another way, the work done depends only on the initial and final position of the particle.

Suppose we throw a object of mass ‘m’ upward suppose it goes up to a height h.

then the work done in throwing object in upward direction w1 = -mgh (use ‘-g’ sign convention )

and the work done while returning to the same path w2 = mgh

total work done W = w1 + w2 = -mgh+mgh = 0

Hence, total energy loss will also be zero in this case.Hence the total workdone in travelling a certain height and falling back to tha same place is zero. This is the property of coservative force as the total workdone depends only on the initial and final positions of the objects. So, Gravitational Force is Conservative Force.

Answers 2 Comments
Dislike Bookmark

Answered on 11/10/2018 Learn CBSE/Class 11/Science/Physics

Assuming the pond has vertical banks and a non-porous bottom and sides (so we need not worry about drainage and such) then the pond level will be increased when we put the boat in the water . A heavier boat will displace more water. When we remove the rock from the boat the boat will displace less water... ...more

Assuming the pond has vertical banks and a non-porous bottom and sides (so we need not worry about drainage and such) then the pond level will be increased when we put the boat in the water . A heavier boat will displace more water. When we remove the rock from the boat the boat will displace less water and the pond  level will decrease.

Answers 2 Comments
Dislike Bookmark

Answered on 01/10/2018 Learn CBSE/Class 11/Science/Physics

Newton’s Law of Cooling states that the rate of change of temperature of a body is proportional to the difference between the temperature of the body and that of the surrounding medium. It is a reasonably accurate approximation in some circumstances. More precisely, let T denote the temperature... ...more

Newton’s Law of Cooling states that the rate of change of temperature of a body is proportional to the difference between the temperature of the body and that of the surrounding medium. It is a reasonably accurate approximation in some circumstances.

More precisely, let T denote the temperature of an object and Tο the ambient temperature.   if t denotes time, then Newton's law states that

dT/dt  = -k(T-Tο)

where k is a positive constant. Thus, if the object temperature is much higher than its surroundings, then  T-Tο is large and positive, so dTdT/dt is large and negative, so the object cools quickly. If the object temperature is only slightly higher than its surroundings, then T-Tο is small positive, and the object cools slowly. So a cup of coffee will cool more quickly if you put it in the refrigerator! 

 

Answers 3 Comments
Dislike Bookmark

Answered on 01/10/2018 Learn CBSE/Class 11/Science/Physics

Newton’s Law of Cooling states that the rate of temperature of the body is proportional to the difference between the temperature of the body and that of the surrounding medium. It is a reasonably accurate approximation in some circumstances. More precisely, let T denote the temperature of an object... ...more

Newton’s Law of Cooling states that the rate of temperature of the body is proportional to the difference between the temperature of the body and that of the surrounding medium. It is a reasonably accurate approximation in some circumstances.

More precisely, let T denote the temperature of an object and Tο the ambient temperature.   if t denotes time, then Newton's law states that

dT/dt  = -k(T-Tο)

where k is a positive constant. Thus, if the object temperature is much higher than its surroundings, then  T-Tο is large and positive, so dTdT/dt is large and negative, so the object cools quickly. If the object temperature is only slightly higher than its surroundings, then T-Tο is small positive, and the object cools slowly. So a cup of coffee will cool more quickly if you put it in the refrigerator! 

 

Answers 3 Comments
Dislike Bookmark

Answered on 30/09/2018 Learn CBSE/Class 11/Science/Physics

mass=1000kg u=0km/hr=0m/s v=54km/hr=15m/s work= change in kinetic energy = 1/2xmxv^2 - 1/2xmxu^2 = 1/2x1000x15^2 - 0 =112500 J power = work/time = 112500/5 = 22500 J/s=22.5 kw from first eqution of motion v=u+at u=0 therfore v=at 15=5a a=3m/s^2 from second equation of motion s=ut+/2at^2 0+1/2*3*5*% s=37.5... ...more

mass=1000kg 
u=0km/hr=0m/s 
v=54km/hr=15m/s 
work= change in kinetic energy 
= 1/2xmxv^2 - 1/2xmxu^2 
= 1/2x1000x15^2 - 0 
=112500 J 
power = work/time 
= 112500/5 = 22500 J/s=22.5 kw

 

from first eqution of motion

v=u+at

u=0

therfore

v=at

15=5a

a=3m/s^2

 

from second equation of motion 

s=ut+/2at^2

0+1/2*3*5*%

s=37.5 m

now v avg=dsance/time=37.5/5=7.5 m/s

 

gaain in KE=KE fina=KE initial

=1/2mv^2-1/2mv2^2

=1/2*1000*15^=112.5kj

 

Answers 2 Comments
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Moumita D. describes herself as Tutor. She conducts classes in Class 10 Tuition, Class 11 Tuition and Class 12 Tuition. Moumita is located in Whitefield, Bangalore. Moumita takes at students Home and Regular Classes- at her Home. She has 5 years of teaching experience . Moumita has completed Master of Science (M.Sc.) from Calcutta University in 2011. She is well versed in Bengali, Hindi and English.

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