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Find the slope of the tangent to curve y = x3 − x + 1 at the point whose x-coordinate is 2.
Asked by Shiv Kohli Last Modified
Answer first, do the derivative of the given function (mean, find dy/dx )
Then put the given value of x in the first derivative.
3(2*2) - 1
11.
Therefore, 11 is the answer.
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Harshit Bhardwaj
The given curve is
.
The slope of the tangent to a curve at (x0, y0) is
.
It is given that x0 = 2.
Hence, the slope of the tangent at the point where the x-coordinate is 2 is given by,
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