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Find the equations of the tangent and normal to the parabola y2 = 4ax at the point (at2, 2at).
The equation of the given parabola is y2 = 4ax.
On differentiating y2 = 4ax with respect to x, we have:
∴The slope of the tangent atis
Then, the equation of the tangent atis given by,
y − 2at =
Now, the slope of the normal atis given by,
Thus, the equation of the normal at (at2, 2at) is given as:
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