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(i) 3x + 2y – 12 = 0 (ii) 4x – 3y = 6 (iii) 3y + 2 = 0.
Asked by Rakhi Last Modified
Answer (i) The given equation is 3x + 2y – 12 = 0.
It can be written as
This equation is of the form
, where a = 4 and b = 6.
Therefore, equation (1) is in the intercept form, where the intercepts on the x and y axes are 4 and 6 respectively.
(ii) The given equation is 4x – 3y = 6.
It can be written as
This equation is of the form, where a = 
and b = –2.
Therefore, equation (2) is in the intercept form, where the intercepts on the x and y axes are and –2 respectively.
(iii) The given equation is 3y + 2 = 0.
It can be written as
This equation is of the form, where a = 0 and b = 
.
Therefore, equation (3) is in the intercept form, where the intercept on the y-axis is and it has no intercept on the x-axis.
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