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It is given that ΔABC ∼ ΔPQR
We know that the corresponding sides of similar triangles are in proportion.
Also, ∠A = ∠P, ∠B = ∠Q, ∠C = ∠R … (2)
Since AD and PM are medians, they will divide their opposite sides.
From equations (1) and (3), we obtain
In ΔABD and ΔPQM,
∠B = ∠Q [Using equation (2)]
(From equation iv)
∴ ΔABD ∼ ΔPQM (By SAS similarity criterion)
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