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C Language > Learn C Language > What is the use of '%d' in a scanf statement?
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What is the use of '%d' in a scanf statement?

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IT Professional

It is the format for inputting integer through scanf()
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"%d" in scanf means it will accept integer input. %d is formating string. It is internal representation in memory
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Primary Teacher

% d is a type of format specifier that aids scanf (). It may also be used to achieve formatted input or output. % d is used in scanf () statement. So that, the value entered is received as an integer. Scanf format string (which stands for "scan formatted") refers to a control parameter used by a class...
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% d is a type of format specifier that aids scanf (). It may also be used to achieve formatted input or output. % d is used in scanf () statement. So that, the value entered is received as an integer.

Scanf format string (which stands for "scan formatted") refers to a control parameter used by a class of functions in the string-processing libraries of various programming languages. The format string specifies a method for reading a string into an arbitrary number of varied data type parameter(s).

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Linux Expert

Open the man page of scanf() it says int scanf(const char *format, ...);so what does that mean ? That means first argument of scanf() is of type char*.And you have provided "%d" and "%d" expects argument nof int type.In short %d in scanf will scan the integer value from user and store into variable.
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Open the man page of scanf() it says

int scanf(const char *format, ...);


so what does that mean ? That means first argument of scanf() is of type char*.
And you have provided "%d" and "%d" expects argument nof int type.

In short %d in scanf will scan the integer value from user and store into variable.
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