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if one third of 100g of 27% aqueous sugar solution is taken in a beaker and 10g of sugar is added to it, the concentration of the resulting solution will be

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44%
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43.85% exact or u can say 44% approximately
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initial solution has a mass of 100g. when 1/3rd o, f the solution is taken, the concentration will remain same. i.e., (100/3)g of solution has ((27*(100/3))/100)g of sugar. = 9g sugar in 33.33g solution. Now 10g sugar is added=> new concentration=(( (9+10)/(33...
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initial solution has a mass of 100g. when 1/3rd o, f the solution is taken, the concentration will remain same. i.e., (100/3)g of solution has ((27*(100/3))/100)g of sugar. = 9g sugar in 33.33g solution. Now 10g sugar is added=> new concentration=(( (9+10)/(33.33+10)) *100)=43.8% read less
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33.6%
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57%
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19%
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