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In the following snippet: /xyz.txt 404 /abc.txt 506 /pqr.txt 404 /xyz.txt 404 /abc.txt 505 /abc.txt 406 /abc.txt 306 /xyz.txt 206 How to write a bash one liner so that the unique text files are counted? For the above snippet the result has to be like: 3 /xyz.txt 4 /abc.txt 1 /pqr.txt Can this scenario be tried in Perl one liner too?

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Experienced in UNIX Shell scripting and core java

Hi Devi, Your while loop solution will not work for all the scenarios. 1. U have not used sort before uniq so in case of unsorted data, the code will not give proper output. 2. Actually we should avoid using while loop in pipe sequence since piping spawns a new shell every time, if you use or assign...
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Hi Devi, Your while loop solution will not work for all the scenarios. 1. U have not used sort before uniq so in case of unsorted data, the code will not give proper output. 2. Actually we should avoid using while loop in pipe sequence since piping spawns a new shell every time, if you use or assign any variable some value inside that while loop, it's scope will only be inside the while loop even if the variable is assigned some initial value before the while loop. U cannot refer the new value of the variable outside the while loop. Since the shell in which while executed would be destroyed once the loop completes. read less
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Trainer

Hi Rahul...I agree with you. Instead of using while loop it is better we use sort, uniq or awk commands for this scenario. Thanks for sharing such a good information and correcting me.
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Python and Unix Professional(10 years IT Exp)

$ awk '{print $1}' sample |sort |uniq -c 4 /abc.txt 1 /pqr.txt 3 /xyz.txt Above command will definitely solve your task. Thanks, Umesh.
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Tutor for Btech IT

nawk '{print $1}' filename|sort |uniq -c
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Experienced in UNIX Shell scripting and core java

I consider that the above file names are in a text file say files.txt. Now to get the unique file count awk '{print $1}' files.txt | sort | uniq -c
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UNIX Scripting Expert

The command should be like below: $ awk '{print $1}' sample |sort |uniq -dc uniq -dc will give you duplicate count .
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Trainer

Mukesh...it has to be in descending order. So, the following command will work: sort -r|uniq -c Thanks for replying.
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Trainer

It can be done with while loop as well, I took the lines from a log file having the following lines: 2015-05-11 23:36 /home.html 200 OK 2015-05-11 23:37 /next2.html 200 OK 2015-05-11 23:37 /xyz3.html 404 Not found 2015-05-11 23:37 /xyz3.html 405 OK Then the following also can be used: cut...
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It can be done with while loop as well, I took the lines from a log file having the following lines: 2015-05-11 23:36 /home.html 200 OK 2015-05-11 23:37 /next2.html 200 OK 2015-05-11 23:37 /xyz3.html 404 Not found 2015-05-11 23:37 /xyz3.html 405 OK Then the following also can be used: cut -d' ' -f3 access.log|uniq|while read line > do > num=`grep -c $line access.log` > echo $num $line > done|sort -r|head -5 read less
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Python Trainer with 5 Years of expirience

$ cat inp.txt /xyz.txt 404 /abc.txt 506 /pqr.txt 404 /xyz.txt 404 /abc.txt 505 /abc.txt 406 /abc.txt 306 /xyz.txt 206 $ cat inp.txt | cut -d" " -f1|sort |uniq -c 4 /abc.txt 1 /pqr.txt 3 /xyz.txt
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Senior DBA, Expert in Sql & No-sql

You can use sort | uniq -c
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