what happens to pendulam clock, if the sorrounding temprature is more than what it is calibrated for?

Pundulam clock's hand is made of metal, i.e pendulam's mass is hanging with a metallic rod.
when ever there is increase in temprature the length of the pendulam clock increases that results in higher time period.

time period is proportional to (lenght)^1/2 , thus the increase in the lenght of the pendulam will result in increase in the time period.

so what's happening are we loosing time(running slower) or our clock is gaining time(running faster).

it's simple: pendulam clock was calibrated for the original length, say n number of oscillation used to calculate 24 hours.
so n =24*60*60/T_original;
T_original is the initial time period of the pendulam.

Now say we are taking T_final(T_final > T_original), so we are getting slower by (T_final - T_original) amount on every time period.
how many time periods(oscillation) we will have to go?
it's n we already calculated, because the watch understands that many oscillation as 24 hours.

so how much time do we loose?

n*(T_final - T_original) per day consisting of 24 hours..............we are slower by this amount of time.

how do we calculate T_final?
please watch out for the next lessons.