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Tejas Class I-V Tuition trainer in Pune/>

Tejas

Sadashiv Peth, Pune, India - 411030.

1 Student

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Referral Discount: Get ₹ 250 off when you make a payment to start classes. Get started by Booking a Demo.

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Identity is verified based on matching the details uploaded by the Tutor with government databases.

Overview

Excellent maths skills. Taught 7th and 8th standard students for scholarship exams. Intend to help students develop math skills and get great scores.

Languages Spoken

Hindi

English

Marathi

Education

Coep 2010

Bachelor of Technology (B.Tech.)

Address

Sadashiv Peth, Pune, India - 411030

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Teaches

Class I-V Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class I-V Tuition

1

Board

State

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class 6 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 6 Tuition

1

Board

State

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class 7 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 7 Tuition

1

Board

State

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class 8 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

1

Board

State

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class 11 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class 12 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class 9 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class 10 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 1-5 do you teach for?

State

2. Have you ever taught in any School or College?

No

3. Which classes do you teach?

I teach Class 10 Tuition, Class 11 Tuition, Class 12 Tuition, Class 6 Tuition, Class 7 Tuition, Class 8 Tuition, Class 9 Tuition and Class I-V Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 1 year.

Contact

Answers by Tejas (2)

Answered on 13/06/2016 Learn Tuition/Class IX-X Tuition

An athlete completes one round a circular track of diameter 200 m in 40 seconds. What will be the distance... ...more
An athlete completes one round a circular track of diameter 200 m in 40 seconds. What will be the distance covered and the displacement at the end of 2 minute and 20 seconds.

HI velocity = circumference/ time v= 3.14*200/40=15.7m/s distance= vxt=2min 20 sec x15.7m/s=140x15.7m= 2198m For displacement 40 seconds are taken to complete 1 rotation Therefore in 140 seconds rotations completed will be 140x1/40 =3.5 rotations this means 3 full rotations and one half rotation... ...more
HI velocity = circumference/ time v= 3.14*200/40=15.7m/s distance= vxt=2min 20 sec x15.7m/s=140x15.7m= 2198m For displacement 40 seconds are taken to complete 1 rotation Therefore in 140 seconds rotations completed will be 140x1/40 =3.5 rotations this means 3 full rotations and one half rotation and athlete will be diametrically opposite to current position Thus displacement will be equal to shortest distance between these points = length of diameter=200m Thanks
Answers 62 Comments
Dislike Bookmark

Answered on 13/06/2016 Learn Tuition/Class IX-X Tuition

An athlete completes one round a circular track of diameter 200 m in 40 seconds. What will be the distance... ...more
An athlete completes one round a circular track of diameter 200 m in 40 seconds. What will be the distance covered and the displacement at the end of 2 minute and 20 seconds.

HI For a circular track : velocity(v)= circumference/time v=3.14*200/40=15.7m/s distance covered in 2min 20 sec(140sec)= velocity * time = 140*15.7=2198m 40 seconds are required to complete 1 rotation therefore in 140 seconds, rotations completed will be =140*1/40=3.5 Thus this means three complete... ...more
HI For a circular track : velocity(v)= circumference/time v=3.14*200/40=15.7m/s distance covered in 2min 20 sec(140sec)= velocity * time = 140*15.7=2198m 40 seconds are required to complete 1 rotation therefore in 140 seconds, rotations completed will be =140*1/40=3.5 Thus this means three complete rotations and one half rotation. Therefore athlete will be diametrically opposite to his position and his displacement will be equal to length of diameter i.e. = 200m
Answers 62 Comments
Dislike Bookmark

Contact

Teaches

Class I-V Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class I-V Tuition

1

Board

State

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class 6 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 6 Tuition

1

Board

State

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class 7 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 7 Tuition

1

Board

State

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class 8 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

1

Board

State

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class 11 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class 12 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class 9 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class 10 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

No Reviews yet!

Answers by Tejas (2)

Answered on 13/06/2016 Learn Tuition/Class IX-X Tuition

An athlete completes one round a circular track of diameter 200 m in 40 seconds. What will be the distance... ...more
An athlete completes one round a circular track of diameter 200 m in 40 seconds. What will be the distance covered and the displacement at the end of 2 minute and 20 seconds.

HI velocity = circumference/ time v= 3.14*200/40=15.7m/s distance= vxt=2min 20 sec x15.7m/s=140x15.7m= 2198m For displacement 40 seconds are taken to complete 1 rotation Therefore in 140 seconds rotations completed will be 140x1/40 =3.5 rotations this means 3 full rotations and one half rotation... ...more
HI velocity = circumference/ time v= 3.14*200/40=15.7m/s distance= vxt=2min 20 sec x15.7m/s=140x15.7m= 2198m For displacement 40 seconds are taken to complete 1 rotation Therefore in 140 seconds rotations completed will be 140x1/40 =3.5 rotations this means 3 full rotations and one half rotation and athlete will be diametrically opposite to current position Thus displacement will be equal to shortest distance between these points = length of diameter=200m Thanks
Answers 62 Comments
Dislike Bookmark

Answered on 13/06/2016 Learn Tuition/Class IX-X Tuition

An athlete completes one round a circular track of diameter 200 m in 40 seconds. What will be the distance... ...more
An athlete completes one round a circular track of diameter 200 m in 40 seconds. What will be the distance covered and the displacement at the end of 2 minute and 20 seconds.

HI For a circular track : velocity(v)= circumference/time v=3.14*200/40=15.7m/s distance covered in 2min 20 sec(140sec)= velocity * time = 140*15.7=2198m 40 seconds are required to complete 1 rotation therefore in 140 seconds, rotations completed will be =140*1/40=3.5 Thus this means three complete... ...more
HI For a circular track : velocity(v)= circumference/time v=3.14*200/40=15.7m/s distance covered in 2min 20 sec(140sec)= velocity * time = 140*15.7=2198m 40 seconds are required to complete 1 rotation therefore in 140 seconds, rotations completed will be =140*1/40=3.5 Thus this means three complete rotations and one half rotation. Therefore athlete will be diametrically opposite to his position and his displacement will be equal to length of diameter i.e. = 200m
Answers 62 Comments
Dislike Bookmark

Contact

Tejas conducts classes in Class 10 Tuition, Class 11 Tuition and Class 12 Tuition. Tejas is located in Sadashiv Peth, Pune. Tejas takes at students Home, Regular Classes- at his Home and Online Classes- via online medium. He has 1 years of teaching experience . Tejas has completed Bachelor of Technology (B.Tech.) from Coep in 2010. He is well versed in Hindi, English and Marathi.

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