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The sum of any two even numbers is always an even number.
Let's denote two even numbers as 2n2n and 2m2m, where nn and mm are integers.
The sum of these two even numbers is: 2n+2m=2(n+m)2n+2m=2(n+m)
Since nn and mm are integers, n+mn+m is also an integer. Therefore, the sum 2(n+m)2(n+m) is an even number because it is divisible by 22. Thus, the sum of any two even numbers is an even number.
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