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Overview

I am an experienced and qualified tutor with over 4 years of experience in teaching all subjects upto class 8th (C.B.S.E) and 2 years in teaching BST and Accountancy to class 11th and 12th.My teaching method is student centred.

Languages Spoken

Hindi

English Proficient

Education

Indraprastha University Pursuing

Bachelor of Education (B.Ed.)

Delhi University 2017

Master of Commerce (M.Com.)

Address

Sector 34, Noida, India - 201307

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Teaches

Class I-V Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class I-V Tuition

4

Fees

₹ 300.0 per hour

Board

CBSE

CBSE Subjects taught

Computers, Mathematics, English, Hindi, Science, Social Science, EVS

Taught in School or College

Yes

Teaching Experience in detail in Class I-V Tuition

I have completed my M.Com and currently perusing B.Ed from one the top college of Indraprastha University. I am currently providing home tuitions and is willing to help the nurturing talents to clear their basic concepts to enhance their skills and overall development.

Class 6 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 6 Tuition

4

Board

CBSE

CBSE Subjects taught

Computers, Hindi, Science, Social Science, Mathematics, EVS

Taught in School or College

Yes

Class 7 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 7 Tuition

4

Board

CBSE

CBSE Subjects taught

Computers, Hindi, Science, Social Science, English, Mathematics, EVS

Taught in School or College

Yes

Class 8 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

2

Board

CBSE

CBSE Subjects taught

Computers, Hindi, Science, Social Science, Mathematics, EVS

Taught in School or College

No

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

2

Board

CBSE

CBSE Subjects taught

Business Studies, Accountancy

Taught in School or College

No

Teaching Experience in detail in Class 11 Tuition

I am a post graduate in commerce and currently pursuing B.ed from IPU.I have two years of experience in teaching 11th and 12th.

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 1-5 do you teach for?

CBSE

2. Have you ever taught in any School or College?

Yes

3. Which classes do you teach?

I teach Class 11 Tuition, Class 6 Tuition, Class 7 Tuition, Class 8 Tuition and Class I-V Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 4 years.

Contact

Answers by Shikha D. (16)

Answered on 18/11/2019 Learn CBSE/Class 6/Maths/Knowing our Numbers/NCERT Solutions/Exercise 1.2

A merchant had Rs 78,592 with her. She placed an order for purchasing 40 radio sets at Rs 1200 each.... ...more
A merchant had Rs 78,592 with her. She placed an order for purchasing 40 radio sets at Rs 1200 each. How much money will remain with her after the purchase

Number of radio sets = 40 Cost of 1 radio set = 1200 Cost of 40 radio sets = 40 x 1200 = 48,000 Total money with merchant = Rs. 78,592 Amount left with the merchant after purchasing 40 radio sets = 78,592 - 48000=... ...more

 Number of radio sets = 40        Cost of 1 radio set = 1200        Cost of 40 radio sets = 40 x 1200 = 48,000                                       Total  money with merchant = Rs. 78,592                                      Amount left with the merchant after purchasing 40 radio sets = 78,592 - 48000= 30,592 Ans.

Answers 3 Comments
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Answered on 18/11/2019 Learn CBSE/Class 6/Maths/Knowing our Numbers/NCERT Solutions/Exercise 1.2

Shekhar is a famous cricket player. He has so far scored 6980 runs in test matches. He wishes to complete... ...more
Shekhar is a famous cricket player. He has so far scored 6980 runs in test matches. He wishes to complete 10, 000 runs. How many more runs does he need?

Runs scored by Shekhar so far = 6,980 Runs he wants to score = 10,000 Runs required to complete 10,000 score = 10,000-6980 =3,020 Ans. ...more

 Runs scored by Shekhar so far = 6,980                                             Runs he wants to score = 10,000 Runs required to complete 10,000 score = 10,000-6980 =3,020 Ans.

Answers 3 Comments
Dislike Bookmark

Answered on 18/11/2019 Learn CBSE/Class 6/Maths/Knowing our Numbers/NCERT Solutions/Exercise 1.2

Medicine is packed in boxes, each weighing 4 kg 500 g. How many such boxes can be loaded in a van which... ...more
Medicine is packed in boxes, each weighing 4 kg 500 g. How many such boxes can be loaded in a van which cannot carry beyond 800 kg?

1kg = 1000g 4kg 500g = 4500g and 800kg = 800x1000= 800000g Number of boxes that can be loaded in the van = 800000 ÷ 4500 =177 maximum boxes that can be loaded in the van=177 Ans ...more

1kg = 1000g                                  4kg 500g = 4500g                      and 800kg = 800x1000= 800000g    Number of boxes that can be loaded in the van = 800000 ÷ 4500 =177                           maximum boxes that can be loaded in the van=177 Ans

Answers 3 Comments
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Answered on 26/10/2019 Learn CBSE/Class 6/Maths/Knowing our Numbers/NCERT Solutions/Exercise 1.2

A vessel has 4 litres and 500 ml of curd. In how many glasses, each of 25 ml capacity, can it be filled? ...more
A vessel has 4 litres and 500 ml of curd. In how many glasses, each of 25 ml capacity, can it be filled?

 

Total quantity of curd in a vessel =4l 500ml= 4500ml (1l=1000ml) No. of glasses needed to fill the vessel = 4500÷25 =180 Ans = 180 glasses
Answers 3 Comments
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Answered on 15/10/2019 Learn CBSE/Class 6/Maths/Knowing our Numbers/NCERT Solutions/Exercise 1.2

Find the difference between the greatest and the least number that can be written using the digits 6,... ...more
Find the difference between the greatest and the least number that can be written using the digits 6, 2, 7, 4, 3 each only once.

The greatest number formed using the given digits= 76432Least number formed using the given digits =23467Difference between the greatest and least number =76432 - 23467= 52,965
Answers 3 Comments
Dislike Bookmark

Contact

View All

Teaches

Class I-V Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class I-V Tuition

4

Fees

₹ 300.0 per hour

Board

CBSE

CBSE Subjects taught

Computers, Mathematics, English, Hindi, Science, Social Science, EVS

Taught in School or College

Yes

Teaching Experience in detail in Class I-V Tuition

I have completed my M.Com and currently perusing B.Ed from one the top college of Indraprastha University. I am currently providing home tuitions and is willing to help the nurturing talents to clear their basic concepts to enhance their skills and overall development.

Class 6 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 6 Tuition

4

Board

CBSE

CBSE Subjects taught

Computers, Hindi, Science, Social Science, Mathematics, EVS

Taught in School or College

Yes

Class 7 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 7 Tuition

4

Board

CBSE

CBSE Subjects taught

Computers, Hindi, Science, Social Science, English, Mathematics, EVS

Taught in School or College

Yes

Class 8 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

2

Board

CBSE

CBSE Subjects taught

Computers, Hindi, Science, Social Science, Mathematics, EVS

Taught in School or College

No

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

2

Board

CBSE

CBSE Subjects taught

Business Studies, Accountancy

Taught in School or College

No

Teaching Experience in detail in Class 11 Tuition

I am a post graduate in commerce and currently pursuing B.ed from IPU.I have two years of experience in teaching 11th and 12th.

No Reviews yet!

Answers by Shikha D. (16)

Answered on 18/11/2019 Learn CBSE/Class 6/Maths/Knowing our Numbers/NCERT Solutions/Exercise 1.2

A merchant had Rs 78,592 with her. She placed an order for purchasing 40 radio sets at Rs 1200 each.... ...more
A merchant had Rs 78,592 with her. She placed an order for purchasing 40 radio sets at Rs 1200 each. How much money will remain with her after the purchase

Number of radio sets = 40 Cost of 1 radio set = 1200 Cost of 40 radio sets = 40 x 1200 = 48,000 Total money with merchant = Rs. 78,592 Amount left with the merchant after purchasing 40 radio sets = 78,592 - 48000=... ...more

 Number of radio sets = 40        Cost of 1 radio set = 1200        Cost of 40 radio sets = 40 x 1200 = 48,000                                       Total  money with merchant = Rs. 78,592                                      Amount left with the merchant after purchasing 40 radio sets = 78,592 - 48000= 30,592 Ans.

Answers 3 Comments
Dislike Bookmark

Answered on 18/11/2019 Learn CBSE/Class 6/Maths/Knowing our Numbers/NCERT Solutions/Exercise 1.2

Shekhar is a famous cricket player. He has so far scored 6980 runs in test matches. He wishes to complete... ...more
Shekhar is a famous cricket player. He has so far scored 6980 runs in test matches. He wishes to complete 10, 000 runs. How many more runs does he need?

Runs scored by Shekhar so far = 6,980 Runs he wants to score = 10,000 Runs required to complete 10,000 score = 10,000-6980 =3,020 Ans. ...more

 Runs scored by Shekhar so far = 6,980                                             Runs he wants to score = 10,000 Runs required to complete 10,000 score = 10,000-6980 =3,020 Ans.

Answers 3 Comments
Dislike Bookmark

Answered on 18/11/2019 Learn CBSE/Class 6/Maths/Knowing our Numbers/NCERT Solutions/Exercise 1.2

Medicine is packed in boxes, each weighing 4 kg 500 g. How many such boxes can be loaded in a van which... ...more
Medicine is packed in boxes, each weighing 4 kg 500 g. How many such boxes can be loaded in a van which cannot carry beyond 800 kg?

1kg = 1000g 4kg 500g = 4500g and 800kg = 800x1000= 800000g Number of boxes that can be loaded in the van = 800000 ÷ 4500 =177 maximum boxes that can be loaded in the van=177 Ans ...more

1kg = 1000g                                  4kg 500g = 4500g                      and 800kg = 800x1000= 800000g    Number of boxes that can be loaded in the van = 800000 ÷ 4500 =177                           maximum boxes that can be loaded in the van=177 Ans

Answers 3 Comments
Dislike Bookmark

Answered on 26/10/2019 Learn CBSE/Class 6/Maths/Knowing our Numbers/NCERT Solutions/Exercise 1.2

A vessel has 4 litres and 500 ml of curd. In how many glasses, each of 25 ml capacity, can it be filled? ...more
A vessel has 4 litres and 500 ml of curd. In how many glasses, each of 25 ml capacity, can it be filled?

 

Total quantity of curd in a vessel =4l 500ml= 4500ml (1l=1000ml) No. of glasses needed to fill the vessel = 4500÷25 =180 Ans = 180 glasses
Answers 3 Comments
Dislike Bookmark

Answered on 15/10/2019 Learn CBSE/Class 6/Maths/Knowing our Numbers/NCERT Solutions/Exercise 1.2

Find the difference between the greatest and the least number that can be written using the digits 6,... ...more
Find the difference between the greatest and the least number that can be written using the digits 6, 2, 7, 4, 3 each only once.

The greatest number formed using the given digits= 76432Least number formed using the given digits =23467Difference between the greatest and least number =76432 - 23467= 52,965
Answers 3 Comments
Dislike Bookmark

Contact

Load More

Shikha D. describes herself as Tutor. She conducts classes in Class 11 Tuition, Class 6 Tuition and Class 7 Tuition. Shikha is located in Sector 34, Noida. Shikha takes at students Home. She has 4 years of teaching experience . Shikha is pursuing Bachelor of Education (B.Ed.) from Indraprastha University. Shikha has completed Master of Commerce (M.Com.) from Delhi University in 2017. She is well versed in Hindi and English.

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