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Find the integrals of the functions
cos 2x cos 4x cos 6x
It is known that,
Find the integrals of the functions
It is known that, 
Find the integrals of the functions
GIVEN function is integral of (sin4x*sin8x).dx
we know:- sinAsinB = 1/2[cos(A-B)-cos(A+B)]
NOW, \sf{\int{sin4x*sin8x}\,dx}
=\sf{\int{1/2[cos(-4x)-cos(12x)]}\,dx}
=\sf{\int{1/2[cos4x-cos12x]}\,dx}
=\sf{1/2[\frac{sin4x}{4}-\frac{sin12x}{12}]+c}
Find the integrals of the functions
sin−1 (cos x)
It is known that,
Substituting in equation (1), we obtain
is equal to
A. tan x + cot x + C
B. tan x + cosec x + C
C. − tan x + cot x + C
D. tan x + sec x + C
Hence, the correct answer is A.
equals
A. − cot (exx) + C
B. tan (xex) + C
C. tan (ex) + C
D. cot (ex) + C
Let exx = t
Hence, the correct answer is B.
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