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Evaluate the integrals
Also, let x = tanθ ⇒ dx = sec2θ dθ
When x = 0, θ = 0 and when x = 1, 
Takingθas first function and sec2θ as second function and integrating by parts, we obtain
Evaluate the integrals
Let x + 2 = t2 ⇒ dx = 2tdt
When x = 0, 
and when x = 2, t = 2
Evaluate the integrals
Let cos x = t ⇒ −sinx dx = dt
When x = 0, t = 1 and when
Evaluate the integrals
Let x + 1 = t ⇒ dx = dt
When x = −1, t = 0 and when x = 1, t = 2
Evaluate the integrals
Let 2x = t ⇒ 2dx = dt
When x = 1, t = 2 and when x = 2, t = 4
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⇒ dx = dt
is
