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H2S, a toxic gas with rotten egg like smell, is used for the qualitative analysis. If the solubility of H2S in water at STP is 0.195 m, calculate Henry’s law constant.
It is given that the solubility of H2S in water at STP is 0.195 m, i.e., 0.195 mol of H2S is dissolved in 1000 g of water.
Moles of water _18-11-08)_Utpal_12_Chemistry_2_12_html_5521aad8.gif){kind=small}
= 55.56 mol
∴Mole fraction of H2S, x_18-11-08)_Utpal_12_Chemistry_2_12_html_m4ff229e0.gif){kind=small}
_18-11-08)_Utpal_12_Chemistry_2_12_html_4ac01d97.gif){kind=small}
= 0.0035
At STP, pressure (p) = 0.987 bar
According to Henry’s law:
p = KHx
_18-11-08)_Utpal_12_Chemistry_2_12_html_70f65685.gif)
= 282 bar
Henry’s law constant for CO2 in water is 1.67 ×108 Pa at 298 K. Calculate the quantity of CO2 in 500 mL of soda water when packed under 2.5 atm CO2 pressure at 298 K.
It is given that:
KH = 1.67 × 108 Pa
_18-11-08)_Utpal_12_Chemistry_2_12_html_m1501b261.gif){kind=small}
= 2.5 atm = 2.5 × 1.01325 × 105 Pa
= 2.533125 × 105 Pa
According to Henry’s law:
_18-11-08)_Utpal_12_Chemistry_2_12_html_m1991adad.gif)
= 0.00152
We can write, _18-11-08)_Utpal_12_Chemistry_2_12_html_6081c2db.gif)
[Since, _18-11-08)_Utpal_12_Chemistry_2_12_html_12ffb063.gif){kind=small}
is negligible as compared to_18-11-08)_Utpal_12_Chemistry_2_12_html_4cb78f2d.gif){kind=small}
]
In 500 mL of soda water, the volume of water = 500 mL
[Neglecting the amount of soda present]
We can write:
500 mL of water = 500 g of water
_18-11-08)_Utpal_12_Chemistry_2_12_html_3a1cd9f4.gif){kind=small}
= 27.78 mol of water
Now, _18-11-08)_Utpal_12_Chemistry_2_12_html_m4f60632c.gif)
_18-11-08)_Utpal_12_Chemistry_2_12_html_21a24334.gif)
Hence, quantity of CO2 in 500 mL of soda water = (0.042 × 44)g
= 1.848 g
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