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Overview

I have been a really proficient student throughout my academic career. Topper of my school in X & XII CBSE board exams. Secured AIR in top 500 (GEN) in IIT JEE 2006 and got into IIT Kanpur. After completing my B.Tech, I worked in Mechanical Engineering core job for 3 years. Secured 99.20% in CAT 2013 and got into IIT Bombay for doing my MBA. Currently working in Gurgaon. Do not have a formal teaching experience in coaching centers but have taught good number of students. Interested in guiding students through their academic courses and help them grow by learning the concepts for long term understanding & not just memorizing the subjects.
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Languages Spoken

English

Hindi

Education

IIT Kanpur 2010

Bachelor of Technology (B.Tech.)

IIT Bombay 2015

Master of Business Administration (M.B.A.)

Address

Powai Iit, Mumbai, India - 400076

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Teaches

Engineering Entrance Coaching classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

MBA Entrance Coaching classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE, ISC/ICSE

ISC/ICSE Subjects taught

Chemistry, Physics, Mathematics

CBSE Subjects taught

Chemistry, Mathematics, Physics

Taught in School or College

No

Teaching Experience in detail in Class 11 Tuition

Have taught students on and off while associated with NGOs while in college as well as post that as well.

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE, ISC/ICSE

ISC/ICSE Subjects taught

Chemistry, Physics, Mathematics

CBSE Subjects taught

Chemistry, Mathematics, Physics

Taught in School or College

No

Teaching Experience in detail in Class 12 Tuition

Have taught students on and off while associated with NGOs while in college as well as post that as well.

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE, ICSE

CBSE Subjects taught

Science, Mathematics

ICSE Subjects taught

Mathematics, Chemistry, Physics

Taught in School or College

No

Teaching Experience in detail in Class 9 Tuition

Have taught students on and off while associated with NGOs while in college as well as post that as well.

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE, ICSE

CBSE Subjects taught

Science, Mathematics

ICSE Subjects taught

Mathematics, Chemistry, Physics

Taught in School or College

No

Teaching Experience in detail in Class 10 Tuition

Have taught students on and off while associated with NGOs while in college as well as post that as well.

Reviews

No Reviews yet!

FAQs

1. Which classes do you teach?

I teach Class 10 Tuition, Class 11 Tuition, Class 12 Tuition, Class 9 Tuition, Engineering Entrance Coaching, IIT JEE Mains Coaching classes, MBA Entrance Coaching and Tuition Classes.

2. Do you provide a demo class?

Yes, I provide a free demo class.

3. How many years of experience do you have?

I have been teaching for less than a year.

Answers by Puneet R. (2)

Answered on 06/01/2016 Learn Tuition/Class XI-XII Tuition (PUC)

NCERT is the best book for class 10th.
Answers 68 Comments
Dislike Bookmark

Answered on 06/01/2016 Learn Tuition/Class XI-XII Tuition (PUC)

Answer: 1/5th of the vessel volume. Let's assume the capacity of vessel be (3+5=) 8 ltrs. Now, the basic principle of all such questions is that when you remove any amount of the mixture, it removes both the liquids in the same ratio as the mixture itself. So, let's suppose we take x ltrs out of the... ...more
Answer: 1/5th of the vessel volume. Let's assume the capacity of vessel be (3+5=) 8 ltrs. Now, the basic principle of all such questions is that when you remove any amount of the mixture, it removes both the liquids in the same ratio as the mixture itself. So, let's suppose we take x ltrs out of the vessel. This means 5x/8 amount of syrup and 3x/8 amount of water gets removed. which means the remaining mixture has (3-(3x/8)) ltrs of water & (5-(5x/8)) syrup. Now when we add x ltrs of water to this mixture, the amount of water and syrup becomes equal. Thus, (x+3-(3x/8)) = (5-(5x/8)) => x=1.6 ltrs. Since we assumed that vessel is 8 ltrs. in volume=> 1.6/8 = 1/5th of the mixture in the vessel needs to be replaced with water. Hope it helps. :)
Answers 24 Comments
Dislike Bookmark

Teaches

Engineering Entrance Coaching classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

MBA Entrance Coaching classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE, ISC/ICSE

ISC/ICSE Subjects taught

Chemistry, Physics, Mathematics

CBSE Subjects taught

Chemistry, Mathematics, Physics

Taught in School or College

No

Teaching Experience in detail in Class 11 Tuition

Have taught students on and off while associated with NGOs while in college as well as post that as well.

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE, ISC/ICSE

ISC/ICSE Subjects taught

Chemistry, Physics, Mathematics

CBSE Subjects taught

Chemistry, Mathematics, Physics

Taught in School or College

No

Teaching Experience in detail in Class 12 Tuition

Have taught students on and off while associated with NGOs while in college as well as post that as well.

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE, ICSE

CBSE Subjects taught

Science, Mathematics

ICSE Subjects taught

Mathematics, Chemistry, Physics

Taught in School or College

No

Teaching Experience in detail in Class 9 Tuition

Have taught students on and off while associated with NGOs while in college as well as post that as well.

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

CBSE, ICSE

CBSE Subjects taught

Science, Mathematics

ICSE Subjects taught

Mathematics, Chemistry, Physics

Taught in School or College

No

Teaching Experience in detail in Class 10 Tuition

Have taught students on and off while associated with NGOs while in college as well as post that as well.

No Reviews yet!

Answers by Puneet R. (2)

Answered on 06/01/2016 Learn Tuition/Class XI-XII Tuition (PUC)

NCERT is the best book for class 10th.
Answers 68 Comments
Dislike Bookmark

Answered on 06/01/2016 Learn Tuition/Class XI-XII Tuition (PUC)

Answer: 1/5th of the vessel volume. Let's assume the capacity of vessel be (3+5=) 8 ltrs. Now, the basic principle of all such questions is that when you remove any amount of the mixture, it removes both the liquids in the same ratio as the mixture itself. So, let's suppose we take x ltrs out of the... ...more
Answer: 1/5th of the vessel volume. Let's assume the capacity of vessel be (3+5=) 8 ltrs. Now, the basic principle of all such questions is that when you remove any amount of the mixture, it removes both the liquids in the same ratio as the mixture itself. So, let's suppose we take x ltrs out of the vessel. This means 5x/8 amount of syrup and 3x/8 amount of water gets removed. which means the remaining mixture has (3-(3x/8)) ltrs of water & (5-(5x/8)) syrup. Now when we add x ltrs of water to this mixture, the amount of water and syrup becomes equal. Thus, (x+3-(3x/8)) = (5-(5x/8)) => x=1.6 ltrs. Since we assumed that vessel is 8 ltrs. in volume=> 1.6/8 = 1/5th of the mixture in the vessel needs to be replaced with water. Hope it helps. :)
Answers 24 Comments
Dislike Bookmark

Puneet R. describes himself as Maths, Physics & Chemistry, IIT Kanpur & IIT Bombay graduate. He conducts classes in Class 10 Tuition, Class 11 Tuition and Class 12 Tuition. Puneet is located in Powai Iit, Mumbai. Puneet takes Regular Classes- at his Home and Online Classes- via online medium. Puneet has completed Bachelor of Technology (B.Tech.) from IIT Kanpur in 2010 and Master of Business Administration (M.B.A.) from IIT Bombay in 2015. He is well versed in English and Hindi.

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