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Linear equations in 2 variables

Linear equations in 2 variables relates to CBSE/Class 9/Mathematics/Algebra

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Linear equations in 2 variables Lessons

Solving Linear Wquation in two Varibles By Substitution Method
https://vz-3ad30922-ba4.b-cdn.net/2d534cba-73c9-4441-adee-53ec64e46332/play_480p.mp4

Linear equations in 2 variables Questions

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Answered on 18 Apr Learn CBSE/Class 9/Mathematics/Algebra/Linear equations in 2 variables

Nazia Khanum

Introduction: In this problem, we are tasked with verifying whether the values x=2x=2 and y=1y=1 satisfy the linear equation 2x+3y=72x+3y=7. Verification: We'll substitute the given values of xx and yy into the equation and check if it holds true. Given Equation: 2x+3y=72x+3y=7 Substituting Given... read more

Introduction: In this problem, we are tasked with verifying whether the values x=2x=2 and y=1y=1 satisfy the linear equation 2x+3y=72x+3y=7.

Verification: We'll substitute the given values of xx and yy into the equation and check if it holds true.

Given Equation: 2x+3y=72x+3y=7

Substituting Given Values:

  • Substitute x=2x=2 and y=1y=1 into the equation. 2(2)+3(1)=72(2)+3(1)=7

Solving the Equation: 4+3=74+3=7 7=77=7

Conclusion:

  • Since the equation simplifies to 7=77=7, it confirms that x=2x=2 and y=1y=1 satisfy the linear equation 2x+3y=72x+3y=7.

Therefore, the given values x=2x=2 and y=1y=1 indeed satisfy the linear equation 2x+3y=72x+3y=7.

 
 
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Answered on 18 Apr Learn CBSE/Class 9/Mathematics/Algebra/Linear equations in 2 variables

Nazia Khanum

Solutions for 2x + 3y = 8 Introduction: In this problem, we're tasked with finding solutions to the equation 2x + 3y = 8. There are multiple solutions that satisfy this equation. Let's explore four of them: Solution 1: Using Integer Values Choose a set of integer values for x and solve for y. Let's... read more

Solutions for 2x + 3y = 8

Introduction: In this problem, we're tasked with finding solutions to the equation 2x + 3y = 8. There are multiple solutions that satisfy this equation. Let's explore four of them:

Solution 1: Using Integer Values

  • Choose a set of integer values for x and solve for y.
  • Let's say x = 2.
  • Substitute x = 2 into the equation: 2(2) + 3y = 8.
  • Solve for y: 4 + 3y = 8.
  • 3y = 8 - 4.
  • 3y = 4.
  • y = 4/3.
  • So, one solution is (2, 4/3).

Solution 2: Using Fractional Values

  • Choose fractional values for x and solve for y.
  • Let's say x = 1/2.
  • Substitute x = 1/2 into the equation: 2(1/2) + 3y = 8.
  • Solve for y: 1 + 3y = 8.
  • 3y = 8 - 1.
  • 3y = 7.
  • y = 7/3.
  • Another solution is (1/2, 7/3).

Solution 3: Using a Variable for y

  • Express y in terms of x and a constant.
  • Rearrange the equation to isolate y: 3y = 8 - 2x.
  • Divide both sides by 3: y = (8 - 2x)/3.
  • So, a solution can be represented as (x, (8 - 2x)/3).

Solution 4: Using Graphical Method

  • Graph the equation on a coordinate plane.
  • Plot the points where the line intersects the x-axis and the y-axis.
  • Determine the coordinates of these points as solutions.
  • By plotting, we find that two points of intersection are (4, 0) and (0, 8/3).
  • Thus, solutions are (4, 0) and (0, 8/3).

Conclusion: The equation 2x + 3y = 8 has multiple solutions, including both integer and fractional values of x and y. Additionally, solutions can also be represented using variables. Graphically, the solutions are the points where the line intersects the axes.

 
 
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Answered on 18 Apr Learn CBSE/Class 9/Mathematics/Algebra/Linear equations in 2 variables

Nazia Khanum

Graphing the Equation x + 2y = 6 To graph the equation x+2y=6x+2y=6, we'll first rewrite it in slope-intercept form (y=mx+by=mx+b): x+2y=6x+2y=6 2y=−x+62y=−x+6 y=−12x+3y=−21x+3 Plotting the Graph To plot the graph, we'll identify two points and draw a line through them: Intercept... read more

Graphing the Equation x + 2y = 6

To graph the equation x+2y=6x+2y=6, we'll first rewrite it in slope-intercept form (y=mx+by=mx+b):

x+2y=6x+2y=6 2y=−x+62y=−x+6 y=−12x+3y=−21x+3

Plotting the Graph

To plot the graph, we'll identify two points and draw a line through them:

  1. Intercept Method:

    • y-intercept (when x = 0): y=−12(0)+3=3y=−21(0)+3=3 Therefore, the y-intercept is (0, 3).
    • x-intercept (when y = 0): 0=−12x+30=−21x+3 −12x=3−21x=3 x=−6x=−6 Therefore, the x-intercept is (-6, 0).
  2. Slope Method: From the slope-intercept form y=−12x+3y=−21x+3, the slope is -1/2, meaning the line decreases by 1 unit in the y-direction for every 2 units in the x-direction.

Plotting the Points and Drawing the Line

Using the intercepts and the slope, we plot the points (0, 3) and (-6, 0), then draw a line through them.

Finding the Value of x when y = -3

Given y=−3y=−3, we substitute this value into the equation y=−12x+3y=−21x+3 and solve for x:

−3=−12x+3−3=−21x+3 −12x=−3−3−21x=−3−3 −12x=−6−21x=−6 x=−6×(−2)x=−6×(−2) x=12x=12

Conclusion

  • The graph of the equation x+2y=6x+2y=6 is a straight line passing through points (0, 3) and (-6, 0).
  • The value of xx when y=−3y=−3 is x=12x=12.
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Answered on 18 Apr Learn CBSE/Class 9/Mathematics/Algebra/Linear equations in 2 variables

Nazia Khanum

Understanding Linear Equations: Linear equations are fundamental in mathematics, representing straight lines on a coordinate plane. They're expressed in the form of ax+b=0ax+b=0, where aa and bb are constants. Identifying Axis: In the context of linear equations, the term "axis" typically refers to... read more

Understanding Linear Equations: Linear equations are fundamental in mathematics, representing straight lines on a coordinate plane. They're expressed in the form of ax+b=0ax+b=0, where aa and bb are constants.

Identifying Axis: In the context of linear equations, the term "axis" typically refers to either the x-axis or the y-axis on a Cartesian plane.

Analyzing the Equation: The linear equation provided is x−2=0x−2=0.

Finding the Axis: To determine which axis the given linear equation is parallel to, let's analyze the equation:

  1. Equation Form:

    • x−2=0x−2=0
  2. Solving for x:

    • x=2x=2
  3. Interpretation:

    • This equation indicates that no matter what value y takes, x will always be 2. This implies that the line represented by this equation is parallel to the y-axis.

Conclusion: The linear equation x−2=0x−2=0 is parallel to the y-axis.

 
 
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