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Lesson Posted 6 days ago Learn Class 9
Jaikumar Veerwani
I specialize in teaching to students from classes 6 to 10 and 11 ,12(commerce), as well as those pursuing...
Lesson Posted on 13 Jun Learn Mathematics
Mathemathics Pro Question for 9th to 12th students .
Savita
Student-focused educational professional with two years of demonstrated experience in helping students...
which one is greater ?
6√10 , 3√4, 2√5
Hind to solve this question : take LCM and then find greater
Question ask in CGL , CHSL , Bank PO .
Question type : Surds and its type .
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Answered 5 days ago Learn The Adventure Of Toto
Deepika Agrawal
"Balancing minds, one ledger at a time." "Counting on expertise to balance your knowledge."
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Affordable fees Flexible Timings Choose between 1-1 and Group class Verified Tutors Answered on 16 May Learn Chapter 9 - The Bond of Love
Deepika Agrawal
"Balancing minds, one ledger at a time." "Counting on expertise to balance your knowledge."
Answered on 16 May Learn Chapter 9 - The Bond of Love
Deepika Agrawal
"Balancing minds, one ledger at a time." "Counting on expertise to balance your knowledge."
Pets Should Be Kept By Those Who Understand Their Needs
Animals are also God's creation; they have sensitivity and emotions. They are wonderful creatures with so many agreeable qualities. Animals feel pain and pleasure, and have emotions. Those who have kept pets in their life know animals feel pain and pleasure.
read lessAnswered 1 day ago Learn Quadrilaterals
Deepika Agrawal
"Balancing minds, one ledger at a time." "Counting on expertise to balance your knowledge."
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Affordable fees Flexible Timings Choose between 1-1 and Group class Verified Tutors Answered 1 day ago Learn Construction
Deepika Agrawal
"Balancing minds, one ledger at a time." "Counting on expertise to balance your knowledge."
Step 1: Draw a line segment AB=13 cm.
Step 2: At A, construct an angle of 45∘ and at B construct an angle of 90∘.
Step 3: Bisect these angles. Let bisector of these angles intersect at point X. Join AX and BX.
Step 4: Draw perpendicular bisectors of AX and BX to intersect AB at Y and Z respectively. Join AB and AC.
Answered 1 day ago Learn Construction
Deepika Agrawal
"Balancing minds, one ledger at a time." "Counting on expertise to balance your knowledge."
Given: In ∆ABC
AB + BC + CA = 10 cm, ∠B = 60° and ∠C = 45°.
Required: To construct ∆ABC.
Steps of Construction :
1. Draw DE = 10 cm
2. At D, construct ∠EDP = 12 of 60°= 30° and at E, construct ∠DEQ =12 of 45° = 22 12∘
3. Let DP and EQ meet at A.
4. Draw perpendicular bisector of AD to meet DE at B.
5. Draw perpendicular bisector of AE to meet DE at C.
6. Join AB and AC. Thus, ABC is the required triangle.
Answered on 18 Apr Learn Linear equations in 2 variables
Nazia Khanum
To draw the graph of the equation 2x−3y=122x−3y=12, let's first rewrite it in slope-intercept form, which is y=mx+by=mx+b, where mm is the slope and bb is the y-intercept.
2x−3y=122x−3y=12
−3y=−2x+12−3y=−2x+12
y=23x−4y=32x−4
Y-intercept: When x=0x=0,
y=23(0)−4y=32(0)−4
y=−4y=−4
So, the y-intercept is (0, -4).
Slope: The coefficient of xx is 2332, which represents the slope.
For every increase of 1 in xx, yy increases by 2332.
For every decrease of 1 in xx, yy decreases by 2332.
Now, let's plot some points to draw the graph:
x = 3: y=23(3)−4=2−4=−2y=32(3)−4=2−4=−2
Point: (3, -2)
x = 6: y=23(6)−4=4−4=0y=32(6)−4=4−4=0
Point: (6, 0)
x = -3: y=23(−3)−4=−2−4=−6y=32(−3)−4=−2−4=−6
Point: (-3, -6)
With these points, we can draw a straight line passing through them.
To find where the graph intersects the x-axis, we set y=0y=0 and solve for xx:
0=23x−40=32x−4
23x=432x=4
x=4×32x=24×3
x=6x=6
So, the graph intersects the x-axis at x=6x=6, which corresponds to the point (6, 0).
To find where the graph intersects the y-axis, we set x=0x=0 and solve for yy:
y=23(0)−4y=32(0)−4
y=−4y=−4
So, the graph intersects the y-axis at y=−4y=−4, which corresponds to the point (0, -4).
This information helps us visualize and understand the behavior of the equation 2x−3y=122x−3y=12 on the coordinate plane.
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Affordable fees Flexible Timings Choose between 1-1 and Group class Verified Tutors Answered on 14 Jun Learn Motion
Adithi S Bhatta
Engineering Student, with 94.5% in 10th Boards and 99th Percentile in JEE Mains
a) Average speed is defined as the total distance traveled divided by the total time taken to travel that distance. Mathematically, it can be expressed as:
Average speed=Total distance/Total time
(b) To calculate the average speed for the entire journey of the bus, we need to determine the total distance traveled and the total time taken for the round trip.
Total Distance: The bus travels a distance of 120 km to the destination and then returns the same distance back. Therefore, the total distance, D = 120km + 120km = 240km
Total Time: To find the total time, we need to calculate the time taken for each leg of the journey separately and then sum these times.
Time to travel to the destination: The bus travels 120 km with a speed of 40 km/h.
t1=Distance/Speed=120 km/40 km/h=3 hours
Time to return: The bus returns the same 120 km distance with a speed of 30 km/h.
t2=DistanceSpeed=120 km30 km/h=4 hours
Therefore, the total time,T for the round trip is:
T=t1+t2=3 hours+4 hours=7 hours
Average Speed: Using the formula for average speed: Average speed=Total distance/Total time=240 km/7 hours
Calculating this gives:
Average speed=240km/7hrs ≈ 34.29 km/h
So, the average speed for the entire journey is approximately 34.29 km/h
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