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Find Best Class 10 Tuition in New Malakpet, Hyderabad

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Class 10 Tuition in New Malakpet, Hyderabad

Select from 29 Online & Offline Class 10 Tuition in your locality

1
Smart Minds Tutorials Class 10 Tuition institute in Hyderabad Sponsored
Narayanguda, Hyderabad
Classes: Class 10 Tuition, C Language and more.

Smart Minds Tutorials provide Spoken English classes, Computer Course classes, Tally Software classes and Handwriting classes. M

1
New Malakpet, Hyderabad
Verified
1 yrs of Exp
300per hour
Classes: Class 10 Tuition, Class I-V Tuition and more.

i am a MBA graduate preparing for competitive exams and also pursuing LLB(final year). can teach students with clarity and easily understandable manner....

2
New Malakpet, Hyderabad
2 yrs of Exp
300per hour
Classes: Class 10 Tuition, Class 9 Tuition

I am an Engineer. Worked in Bharat Electronics limited (BEL) Bangalore. Currently, studying for UPSC (civil services). Available to give online/home...

3
New Malakpet, Hyderabad
10 yrs of Exp
Classes: Class 10 Tuition, Class 8 Tuition and more.

I am a Mathematics teacher basically but can teach all subjects except hindi for high school children. I am a engineering graduate from Osmania University...

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4
New Malakpet, Hyderabad
Verified
7 yrs of Exp
Classes: Class 10 Tuition, Class 7 Tuition and more.

I am a lecturer of microbiology with 5 years of experience. I am giving home tuition since past 7 years. I have a masters degree in microbiology from...

5
New Malakpet, Hyderabad
2 yrs of Exp
350per hour
Classes: Class 10 Tuition, Class 11 Tuition

I am pursuing Engineering in Computer Science. I give classes to students at their home or online. I have passed all my studies in excellent grad...

6
New Malakpet, Hyderabad
4 yrs of Exp
200per hour
Classes: Class 10 Tuition, Class 12 Tuition and more.

I am a medical student. I am good at physics and chemistry. I like to spend my time productively. I like sharing my knowledge to others.

7
New Malakpet, Hyderabad
Classes: Class 10 Tuition, BTech Tuition and more.

I am a engineer in Electronic stream, and i am giving tutor home tuitions since 2016 , i am certified in mathematics, physics and electronics sub...

8
New Malakpet, Hyderabad
1 yrs of Exp
Classes: Class 10 Tuition, Class I-V Tuition and more.

I am student from department of Electronics and communications engineering, I have a 1 year experience as campus ambassador which mainly focus In...

9
New Malakpet, Hyderabad
7 yrs of Exp
Classes: Class 10 Tuition, Class 9 Tuition and more.

I am a student at IIT Madras. teaching since 2015. I generally teach mathematics and chemistry. I believe in teaching and learning.I motivate students...

10
New Malakpet, Hyderabad
1 yrs of Exp
Classes: Class 10 Tuition

I did my graduation in commerce and have completed CA-IPCC. I also have working knowledge in audit & finance as I did my CA-Internship in Ernst and...

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    Key highlights about Class 10 Tuition

    ✅ Free Demo Class : Available
    ✅ Average price : ₹350/hr
    ✅ Tutors available : 29
    ✅ Class format : Online or Offline classes

    FAQ

    How do I find the best Class 10 Tuition in New Malakpet, Hyderabad near me?

    You can browse the list of best Class 10 tutors on UrbanPro.com. You can even book a free demo class to decide which Tutor to start classes with.

    What is the typical Fee charged for Class 10 Tuition in New Malakpet, Hyderabad?

    The fee charged varies between online and offline classes. Generally you get the best quality at the lowest cost in the online classes, as the best tutors don’t like to travel to the Student’s location.

    Monthly Fee for 1-1 Classes

    ₹3,600 - ₹4,800 for 12 classes per month

    Hourly Fee for 1-1 Classes

    ₹300 - ₹400

    Monthly Fee for Group Classes

    ₹2,880 - ₹3,840 for 12 classes per month

    Hourly Fee for Group Classes

    ₹240 - ₹320

    Monthly Fee for Class 10 Tuition at home

    ₹6,000 - ₹14,400 for 12 classes per month

    Hourly Fee for Class 10 Tuition at home

    ₹500 - ₹1,200

    Monthly Fee for Online Class 10 Tuition

    ₹3,600 - ₹4,800 for 12 classes per month

    Hourly Fee for Online Class 10 Tuition

    ₹300 - ₹400

    Does joining Class 10 Tuition help?

    It definitely helps to join Class 10 Tuition in New Malakpet, Hyderabad, as you get the desired motivation from a Teacher to learn. If you need personal attention and if your budget allows, select 1-1 Class. If you need peer interaction or have budget constraints, select a Group Class.

    Where can I find Class 10 Tuition near me?

    UrbanPro has a list of best Class 10 Tuition

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    Class 10 Tuition Questions

    Which sector has emerged as the largest producing sector in the Indian economy in the last decade? Give reasons.

    It appears that agriculture ..lot of people 80 to 90 was in it in 190..by now in2018..dependant ratio...

    Why we considered people as a resource?

    becuaPeople are considered to be a resource because they give resource value to all other resourcesse

    Here are six sentences with some words in italics. Find phrases from the text that have the same meaning....

    (i) keep many visitors away (ii) as one story goes (iii)are more than willing to recount (iv) the most...

    what is dynamic motion ?

    Dynamics is a branch of applied mathematics (specifically classical mechanics) concerned with the study...

    Class 10 Tuition Lessons

    Oxidation -Reduction Reaction - Class 10

    https://vz-3ad30922-ba4.b-cdn.net/7c9e6f7a-069c-4690-9740-0b214483f4b9/play_480p.mp4

    गुण सन्धि

    गुण सन्‍धि (आद् गुुण:)— यदि 'अ' या 'आ' के बाद 'इ' या 'ई' आए। दोनों के स्‍थान पर ए एकादेश हो जाता है। इसी तरह यदि 'अ' या 'आ' के बाद 'उ'...

    Rotation of a Shape

    * Rotation is nothing but rotating an object through an angle of 90 degrees, 180 degrees, 270 degrees either clockwise or anticlockwise. * For rotating...

    वृद्धि संधि

    वृद्धि‍ सन्धि (वृद्धिरेचि)— यदि 'अ' या 'आ' के बाद 'ए' या 'ऐ' आए तो दोनों के स्‍थान पर 'ऐ' एकादेश हो जाता है। इसी तरह 'अ' या 'आ' के बाद...

    Find The Length Of 3rd Side Of The Triangle (Important)

    Question: Solution: (2a)^2 + b^2 = 18^24a^2+b^2 = 324(2b)^2+a^2 = 24^24b^2+a^2...

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