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Ravi Kumar Engineering Entrance trainer in Delhi

Ravi Kumar

Chemistry tutor with 5 year experience in competitive exams like IIT JEE, NEET, etc.

Mukherjee Nagar, Delhi, India - 110009.

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Referral Discount: Get ₹ 250 off when you make a payment to start classes. Get started by Booking a Demo.

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Overview

I am an experienced, qualified tutor with over 5 years of experience in teaching chemistry across board exams and competitive exams like IIT JEE, NEET, etc. I completed my graduation from HINDU COLLEGE UNIVERSITY OF DELHI in chemistry and I am studying in final year of masters in IIT BOMBAY. I also have one year doubt faculty experience in ASF Institute and of making study material also. My achievements are as following during my academics:
AIR-4 in IIT JAM 2018
AIR-17 in CSIR NET DECEMBER 2018
AIR-49 in GATE 2019
AIR-11 in CSIR NET JUNE 2019
Selected in BARC 2019 in written exam.

Languages Spoken

English

Hindi

Education

Hindu college, university of Delhi 2017

Bachelor of Science (B.Sc.)

IIT BOMBAY 2018

JAM SCORECARD 2018

Address

Mukherjee Nagar, Delhi, India - 110009

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Teaches

Engineering Entrance Coaching classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Engineering Entrance Coaching classes

5

Engineering Entrance Exams

Delhi CEE Coaching Classes, BITSAT Coaching Classes, GATE Coaching Classes, IIT JEE Coaching Classes, EAMCET

IITJEE Coaching

IIT JEE Foundation Course, IIT JEE Integrated Coaching, IIT JEE Advanced Coaching, IIT JEE Mains Coaching, IIT JEE Crash Course

Type of class

Crash Course, Regular Classes

IIT-JEE Subjects

Chemistry

Medical Entrance Coaching classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Medical Entrance Coaching classes

5

Teaches for following exams

PMT Coaching, AIIMS Coaching, Others, AIPMT Coaching

Type of class

Crash Course, Regular Classes

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

5

NIOS Subjects taught

Chemistry

Board

State, CBSE, ISC/ICSE, IGCSE, International Baccalaureate, NIOS

IB Subjects taught

Chemistry

ISC/ICSE Subjects taught

Chemistry

CBSE Subjects taught

Chemistry

IGCSE Subjects taught

Chemistry

Taught in School or College

Yes

State Syllabus Subjects taught

Chemistry

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

5

NIOS Subjects taught

Chemistry

Board

State, CBSE, ISC/ICSE, IGCSE, International Baccalaureate, NIOS

IB Subjects taught

Chemistry

ISC/ICSE Subjects taught

Chemistry

CBSE Subjects taught

Chemistry

IGCSE Subjects taught

Chemistry

Taught in School or College

Yes

State Syllabus Subjects taught

Chemistry

CSIR NET classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in CSIR NET classes

3

CSIR NET Paper

Chemical sciences

Reviews

No Reviews yet!

FAQs

1. Which classes do you teach?

I teach CSIR NET, Class 11 Tuition, Class 12 Tuition, Engineering Entrance Coaching and Medical Entrance Coaching Classes.

2. Do you provide a demo class?

Yes, I provide a free demo class.

3. How many years of experience do you have?

I have been teaching for 5 years.

Contact

Answers by Ravi Kumar (3)

Answered on 16/10/2018 Learn CBSE/Class 11/Science/Chemistry/Chemical Bonding and Molecular Structure +1 CBSE/Class 11/Science/Chemistry

Explain why PC15 is trigonal bipyramidal whereas IF5 is square pyramidal.

Firstly we determine no. of hybrid orbitals by this formula H=1/2(v+m-c+a) where,v-total no of valence electron on central atom,m-total no of surrounding monovalent atoms , c-charge of cation,a-charge of anion. For PCl5,H=1/2(5+5-0+0)=5,sp3d hybridization and shape trigonal bipyramidal and for... ...more

Firstly we determine no. of hybrid orbitals by this formula H=1/2(v+m-c+a) where,v-total no of valence electron on central atom,m-total no of surrounding monovalent atoms , c-charge of cation,a-charge of anion.         For PCl5,H=1/2(5+5-0+0)=5,sp3d hybridization and shape trigonal bipyramidal and for IF5 H=1/2(7+5-0+0)=6,sp3d2 hybridization and shape square pyramidal.

Answers 2 Comments
Dislike Bookmark

Answered on 13/10/2018 Learn CBSE/Class 11/Science/Chemistry +1 CBSE/Class 11/Science/Chemistry/Chemical Bonding and Molecular Structure

In which of the following substances will hydrogen bond be strongest? (a) HCl (b) H20 ... ...more
In which of the following substances will hydrogen bond be strongest?
(a) HCl
(b) H20                     
(c) HI                      
(d) H2S

H2O because H bonding strength depends on the electronegativity difference between H and other atom (F,O,N, etc.). Greater the electronegativity difference greater will be the strength of H bonding.
Answers 12 Comments
Dislike Bookmark

Answered on 11/10/2018 Learn CBSE/Class 11/Science/Chemistry +1 CBSE/Class 11/Science/Chemistry/Chemical Bonding and Molecular Structure

CO is isoelectronic with (a) NO+ (b) N2 (c) SnCl2 (d) N02 ...more
CO is isoelectronic with
(a) NO+
(b) N2                       
(c) SnCl2                  
(d) N02

CO is isoelectronic with both NO+ and N2 because both have 14 e- which are equal to CO e-s . For isoelectronic specie we see total e-s present in specie not only valence e-s.
Answers 8 Comments
Dislike Bookmark

Contact

Teaches

Engineering Entrance Coaching classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Engineering Entrance Coaching classes

5

Engineering Entrance Exams

Delhi CEE Coaching Classes, BITSAT Coaching Classes, GATE Coaching Classes, IIT JEE Coaching Classes, EAMCET

IITJEE Coaching

IIT JEE Foundation Course, IIT JEE Integrated Coaching, IIT JEE Advanced Coaching, IIT JEE Mains Coaching, IIT JEE Crash Course

Type of class

Crash Course, Regular Classes

IIT-JEE Subjects

Chemistry

Medical Entrance Coaching classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Medical Entrance Coaching classes

5

Teaches for following exams

PMT Coaching, AIIMS Coaching, Others, AIPMT Coaching

Type of class

Crash Course, Regular Classes

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

5

NIOS Subjects taught

Chemistry

Board

State, CBSE, ISC/ICSE, IGCSE, International Baccalaureate, NIOS

IB Subjects taught

Chemistry

ISC/ICSE Subjects taught

Chemistry

CBSE Subjects taught

Chemistry

IGCSE Subjects taught

Chemistry

Taught in School or College

Yes

State Syllabus Subjects taught

Chemistry

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

5

NIOS Subjects taught

Chemistry

Board

State, CBSE, ISC/ICSE, IGCSE, International Baccalaureate, NIOS

IB Subjects taught

Chemistry

ISC/ICSE Subjects taught

Chemistry

CBSE Subjects taught

Chemistry

IGCSE Subjects taught

Chemistry

Taught in School or College

Yes

State Syllabus Subjects taught

Chemistry

CSIR NET classes

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in CSIR NET classes

3

CSIR NET Paper

Chemical sciences

No Reviews yet!

Answers by Ravi Kumar (3)

Answered on 16/10/2018 Learn CBSE/Class 11/Science/Chemistry/Chemical Bonding and Molecular Structure +1 CBSE/Class 11/Science/Chemistry

Explain why PC15 is trigonal bipyramidal whereas IF5 is square pyramidal.

Firstly we determine no. of hybrid orbitals by this formula H=1/2(v+m-c+a) where,v-total no of valence electron on central atom,m-total no of surrounding monovalent atoms , c-charge of cation,a-charge of anion. For PCl5,H=1/2(5+5-0+0)=5,sp3d hybridization and shape trigonal bipyramidal and for... ...more

Firstly we determine no. of hybrid orbitals by this formula H=1/2(v+m-c+a) where,v-total no of valence electron on central atom,m-total no of surrounding monovalent atoms , c-charge of cation,a-charge of anion.         For PCl5,H=1/2(5+5-0+0)=5,sp3d hybridization and shape trigonal bipyramidal and for IF5 H=1/2(7+5-0+0)=6,sp3d2 hybridization and shape square pyramidal.

Answers 2 Comments
Dislike Bookmark

Answered on 13/10/2018 Learn CBSE/Class 11/Science/Chemistry +1 CBSE/Class 11/Science/Chemistry/Chemical Bonding and Molecular Structure

In which of the following substances will hydrogen bond be strongest? (a) HCl (b) H20 ... ...more
In which of the following substances will hydrogen bond be strongest?
(a) HCl
(b) H20                     
(c) HI                      
(d) H2S

H2O because H bonding strength depends on the electronegativity difference between H and other atom (F,O,N, etc.). Greater the electronegativity difference greater will be the strength of H bonding.
Answers 12 Comments
Dislike Bookmark

Answered on 11/10/2018 Learn CBSE/Class 11/Science/Chemistry +1 CBSE/Class 11/Science/Chemistry/Chemical Bonding and Molecular Structure

CO is isoelectronic with (a) NO+ (b) N2 (c) SnCl2 (d) N02 ...more
CO is isoelectronic with
(a) NO+
(b) N2                       
(c) SnCl2                  
(d) N02

CO is isoelectronic with both NO+ and N2 because both have 14 e- which are equal to CO e-s . For isoelectronic specie we see total e-s present in specie not only valence e-s.
Answers 8 Comments
Dislike Bookmark

Contact

Ravi Kumar describes himself as Chemistry tutor with 5 year experience in competitive exams like IIT JEE, NEET, etc.. He conducts classes in CSIR NET, Class 11 Tuition and Class 12 Tuition. Ravi is located in Mukherjee Nagar, Delhi. Ravi takes at students Home and Online Classes- via online medium. He has 5 years of teaching experience . Ravi has completed Bachelor of Science (B.Sc.) from Hindu college, university of Delhi in 2017. He is well versed in English and Hindi.

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