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Post a LessonAnswered on 10 Apr Learn CBSE/Class 11/Science/Chemistry/Chemical Bonding and Molecular Structure
Sadika
Use the molecular orbital energy level diagram to show that N2 would be expected to have a triple bond, F2 a single bond and Ne2 no bond.
read lessAnswered on 10 Apr Learn CBSE/Class 11/Science/Chemistry/Chemical Bonding and Molecular Structure
Sadika
To arrange the bonds in order of increasing ionic character, we need to consider the electronegativities of the atoms involved in each bond. Ionic character increases as the electronegativity difference between the atoms in the bond increases. The greater the electronegativity difference, the more polar the bond becomes, and it approaches the characteristics of an ionic bond.
Here are the electronegativities of the elements involved:
Now, let's arrange the bonds in order of increasing ionic character:
C-H bond: Carbon (C) and hydrogen (H) have similar electronegativities, so the C-H bond is considered to be nonpolar covalent. There is no significant electronegativity difference between carbon and hydrogen, so the bond has minimal ionic character.
N-H bond: Nitrogen (N) has a higher electronegativity than carbon but lower than fluorine and oxygen. The electronegativity difference between nitrogen and hydrogen is higher than that between carbon and hydrogen, resulting in a more polar bond compared to C-H. However, it is still predominantly covalent in nature.
O-H bond: Oxygen (O) is more electronegative than nitrogen, resulting in a higher electronegativity difference between oxygen and hydrogen. The O-H bond is more polar compared to the N-H bond, indicating higher ionic character.
F-H bond: Fluorine (F) is the most electronegative element in the given list. The electronegativity difference between fluorine and hydrogen is the highest among the bonds listed. Therefore, the F-H bond exhibits the highest ionic character among the given bonds.
So, the order of increasing ionic character is: C-H < N-H < O-H < F-H
Answered on 10 Apr Learn CBSE/Class 11/Science/Chemistry/Chemical Bonding and Molecular Structure
Sadika
The bond order in molecules indicates the number of chemical bonds between two atoms. It is calculated as the difference between the number of bonding electrons and the number of antibonding electrons, divided by two. Therefore, the effect of the processes described on the bond order in N2 and O2 can be analyzed by considering the changes in the number of bonding and antibonding electrons.
Let's analyze the effect of each process on the bond order in N2 and O2:
(i) N2 → N+2 + e– (loss of one electron)
In the process described, one electron is removed from the N2 molecule, resulting in the formation of N+2 ion and one additional electron. This electron removal affects the bonding and antibonding orbitals differently.
Bonding orbitals (σ and π): The removal of an electron does not directly affect the bonding orbitals. Therefore, the number of bonding electrons remains the same.
Antibonding orbitals (σ and π):** With the removal of one electron, one fewer electron will occupy the antibonding orbitals.
Since the bond order is calculated as the difference between the number of bonding and antibonding electrons divided by two, the removal of one electron increases the bond order by 0.5.
(ii) O2 → O+2 + e– (loss of one electron)
In this process, one electron is removed from the O2 molecule, resulting in the formation of O+2 ion and one additional electron. Similar to the case of nitrogen, the removal of an electron affects the bonding and antibonding orbitals differently.
Bonding orbitals (σ and π): The removal of an electron does not directly affect the bonding orbitals, so the number of bonding electrons remains the same.
Antibonding orbitals (σ and π):** With the removal of one electron, one fewer electron will occupy the antibonding orbitals.
As with nitrogen, the removal of one electron increases the bond order of oxygen by 0.5.
In summary, the effect of both processes (removing one electron) is to increase the bond order by 0.5 in both N2 and O2 molecules.
Answered on 29 Mar Learn CBSE/Class 11/Science/Chemistry/Chemical Bonding and Molecular Structure
Nazia Khanum
Best Chemistry Branch for MSc in Chemistry
As an experienced tutor registered on UrbanPro.com, I understand the importance of choosing the right branch for pursuing MSc in Chemistry. Here are some insights into the best branches for MSc in Chemistry:
1. Organic Chemistry:
2. Inorganic Chemistry:
3. Physical Chemistry:
4. Analytical Chemistry:
5. Biochemistry:
Choosing the Right Branch:
Conclusion: Selecting the best branch for MSc in Chemistry depends on individual interests, career objectives, and the scope of the field. Each branch offers unique opportunities for specialization and career advancement in various industries. It's essential to explore the curriculum, research opportunities, and future prospects before making a decision.
Answered on 29 Mar Learn CBSE/Class 11/Science/Chemistry/Chemical Bonding and Molecular Structure
Nazia Khanum
Best Chemistry Branch for MSc in Chemistry
As an experienced tutor registered on UrbanPro.com, I understand the importance of choosing the right branch for pursuing MSc in Chemistry. Here are some insights into the best branches for MSc in Chemistry:
1. Organic Chemistry:
2. Inorganic Chemistry:
3. Physical Chemistry:
4. Analytical Chemistry:
5. Biochemistry:
Choosing the Right Branch:
Conclusion: Selecting the best branch for MSc in Chemistry depends on individual interests, career objectives, and the scope of the field. Each branch offers unique opportunities for specialization and career advancement in various industries. It's essential to explore the curriculum, research opportunities, and future prospects before making a decision.
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