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Overview

Naipal Singh describes himself as Maths Tutor. He conducts classes in BPM 10G, BSc Tuition and Class 10 Tuition. Naipal is located in Govind Puri, Delhi. Naipal takes at students Home. Naipal is pursuing Bachelor of Science (B.Sc.) from Acharya Narendra Dev college University of Delhi . He is well versed in Hindi.

Languages Spoken

Hindi

Education

Acharya Narendra Dev college University of Delhi Pursuing

Bachelor of Science (B.Sc.)

Address

Govind Puri, Delhi, India - 110019

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Teaches

Sun Solaris 10 Training

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Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

BPM 10G Training

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Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Class 9 Tuition

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Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

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No

Class 10 Tuition

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Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State

Taught in School or College

No

Class 6 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State

Taught in School or College

No

Class 7 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State

Taught in School or College

No

Class 8 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State

Taught in School or College

No

Class I-V Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State

Taught in School or College

No

State Syllabus Subjects taught

English, Mathematics, Hindi

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State

Taught in School or College

No

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State

Taught in School or College

No

BSc Tuition

Class Location

Online (video chat via skype, google hangout etc)

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FAQs

1. Which classes do you teach?

I teach BPM 10G, BSc Tuition, Class 10 Tuition, Class 11 Tuition, Class 12 Tuition, Class 6 Tuition, Class 7 Tuition, Class 8 Tuition, Class 9 Tuition and Class I-V Tuition Classes.

2. Do you provide a demo class?

Yes, I provide a free demo class.

3. How many years of experience do you have?

I have been teaching for less than a year.

Contact

Answers by Naipal Singh (1)

Answered on 12/11/2017 Learn Tuition/Class VI-VIII Tuition

A train travelling at 60km per hour leaves station A at 3.00.p .m. and an another train leaves the same... ...more
A train travelling at 60km per hour leaves station A at 3.00.p .m. and an another train leaves the same station in the same direction at 5.00 p.m. at the speed of 75 km per hr.How many kilometres from station A will the trains be together?

After 600 km i.e. after 8 hours or 1 bje next day both trains will be together Solution Let both trains will meet at distance X km from station A Then according the question Let 2nd train will travel X distance in T time So. Distance =speed ×time X=75×T And by 1st train... ...more
After 600 km i.e. after 8 hours or 1 bje next day both trains will be together Solution Let both trains will meet at distance X km from station A Then according the question Let 2nd train will travel X distance in T time So. Distance =speed ×time X=75×T And by 1st train X=60(T+2) X=60T+120 NOW. 75T=60T+120 15T=120 T=8 hours So 2nd train will be travelled distance in 8 hours =75×8 =600km And 1st train will be travelled distance in 10 hours =60×10 =600km Hence after travelling 600km both trains will be together
Answers 100 Comments
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Teaches

Sun Solaris 10 Training

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

BPM 10G Training

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Class 9 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State

Taught in School or College

No

Class 10 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State

Taught in School or College

No

Class 6 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State

Taught in School or College

No

Class 7 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State

Taught in School or College

No

Class 8 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State

Taught in School or College

No

Class I-V Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State

Taught in School or College

No

State Syllabus Subjects taught

English, Mathematics, Hindi

Class 11 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State

Taught in School or College

No

Class 12 Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Board

State

Taught in School or College

No

BSc Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

No Reviews yet!

Answers by Naipal Singh (1)

Answered on 12/11/2017 Learn Tuition/Class VI-VIII Tuition

A train travelling at 60km per hour leaves station A at 3.00.p .m. and an another train leaves the same... ...more
A train travelling at 60km per hour leaves station A at 3.00.p .m. and an another train leaves the same station in the same direction at 5.00 p.m. at the speed of 75 km per hr.How many kilometres from station A will the trains be together?

After 600 km i.e. after 8 hours or 1 bje next day both trains will be together Solution Let both trains will meet at distance X km from station A Then according the question Let 2nd train will travel X distance in T time So. Distance =speed ×time X=75×T And by 1st train... ...more
After 600 km i.e. after 8 hours or 1 bje next day both trains will be together Solution Let both trains will meet at distance X km from station A Then according the question Let 2nd train will travel X distance in T time So. Distance =speed ×time X=75×T And by 1st train X=60(T+2) X=60T+120 NOW. 75T=60T+120 15T=120 T=8 hours So 2nd train will be travelled distance in 8 hours =75×8 =600km And 1st train will be travelled distance in 10 hours =60×10 =600km Hence after travelling 600km both trains will be together
Answers 100 Comments
Dislike Bookmark

Contact

Naipal Singh describes himself as Maths Tutor. He conducts classes in BPM 10G, BSc Tuition and Class 10 Tuition. Naipal is located in Govind Puri, Delhi. Naipal takes at students Home. Naipal is pursuing Bachelor of Science (B.Sc.) from Acharya Narendra Dev college University of Delhi . He is well versed in Hindi.

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