Pusa, Delhi, India - 110012.
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Hindi Mother Tongue (Native)
Delhi University 1977
Bachelor of Arts (B.A.)
Yogrish Astro Research Centre 2023
Advance Vedic Astrology
Pusa, Delhi, India - 110012
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Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Astrology Classes
3
1. Which classes do you teach?
I teach Astrology Class.
2. Do you provide a demo class?
Yes, I provide a free demo class.
3. How many years of experience do you have?
I have been teaching for 3 years.
Answered on 26 Feb Learn CBSE/Class 8/Maths/Factorization
To factorize the quadratic expression x2+6x+8x2+6x+8, we're looking for two binomials of the form (x+p)(x+q)(x+p)(x+q) where pp and qq are numbers such that:
(x+p)(x+q)=x2+(p+q)x+pq(x+p)(x+q)=x2+(p+q)x+pq
In this case, we want p+qp+q to be equal to the coefficient of xx in the given expression (which is 6) and pqpq to be equal to the constant term (which is 8).
Let's find pp and qq:
p+q=6p+q=6 pq=8pq=8
The pairs of numbers that satisfy these conditions are p=2p=2 and q=4q=4.
Therefore, the factorization is:
x2+6x+8=(x+2)(x+4)x2+6x+8=(x+2)(x+4)
Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Astrology Classes
3
Answered on 26 Feb Learn CBSE/Class 8/Maths/Factorization
To factorize the quadratic expression x2+6x+8x2+6x+8, we're looking for two binomials of the form (x+p)(x+q)(x+p)(x+q) where pp and qq are numbers such that:
(x+p)(x+q)=x2+(p+q)x+pq(x+p)(x+q)=x2+(p+q)x+pq
In this case, we want p+qp+q to be equal to the coefficient of xx in the given expression (which is 6) and pqpq to be equal to the constant term (which is 8).
Let's find pp and qq:
p+q=6p+q=6 pq=8pq=8
The pairs of numbers that satisfy these conditions are p=2p=2 and q=4q=4.
Therefore, the factorization is:
x2+6x+8=(x+2)(x+4)x2+6x+8=(x+2)(x+4)
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