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Factorization

Factorization relates to CBSE/Class 8/Maths

Top Tutors who teach Factorization

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Avishake Chatterjee Class 8 Tuition trainer in Kolkata Featured
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Deepak Joshi Class 8 Tuition trainer in Gurgaon Featured
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Indrajeet Kumar Sinha Class 8 Tuition trainer in Noida Featured
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Pooja Patel . Class 8 Tuition trainer in Indore Featured
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I bring over four years of hands-on experience in mathematics and science, making complex topics easy to understand. My deep knowledge in areas like...

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Whitefield, Bangalore
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20 yrs of Exp
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Debabrato Chatterjee Class 8 Tuition trainer in Thane Featured
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This is Debabrato Chatterjee online Maths and Science tutor having 13+years of experience. I have already and presently teaching students of IB,...

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Ottapalam, Ottapalam
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I am a resident of Kerala working in a CBSE school.I got the opportunity of working with Kendreya Vidyalaya (Ottapalam) , Cambridge Public School...

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Vidya G. Class 8 Tuition trainer in Mira-Bhayandar Featured
Mira Road West, Mira-Bhayandar
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18 yrs of Exp
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I have done my Masters in Education. I am an experienced, qualified teacher and tutor with over 15 yrs if experience in teaching maths and English,...

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Ajay A S Class 8 Tuition trainer in Kota Featured
Talwandi Sector-B, Kota
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My teaching exp.11 year in most reputed coaching in india. Mentor of jee top rank air-12 yatis agrawal, 19, 28 many more in top 100 in jee adavnced....

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Shivam Pandey Class 8 Tuition trainer in Delhi Featured
Laxmi Nagar Vishwakarma Park, Delhi
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300per hour
Classes: Class 8 Tuition, Class 6 Tuition and more.

As a teacher I am teaching 8 th stdandrd students from last 4 years in tutions and 3 years in school . In school my main subject is maths but as a...

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Answered on 26 Feb Learn CBSE/Class 8/Maths/Factorization

Nazia Khanum

As a registered tutor on UrbanPro.com specializing in Class 7 Tuition, I understand the importance of providing clear and structured explanations for mathematical problems. Let's delve into the factorization of the given polynomial expression: Problem Statement Factorize the polynomial expression: 54x²... read more

As a registered tutor on UrbanPro.com specializing in Class 7 Tuition, I understand the importance of providing clear and structured explanations for mathematical problems. Let's delve into the factorization of the given polynomial expression:

Problem Statement

Factorize the polynomial expression: 54x² + 42x³ – 30x⁴

Solution Steps

Step 1: Identify the Common Factor

The first step in factoring a polynomial is to identify the common factor of all the terms. In this case, the common factor is 6x².

  • Expression after factoring out the common factor: 6x2(9+7x−5x2)6x2(9+7x−5x2)

Step 2: Factorize the Quadratic Expression

Now, we need to factorize the quadratic expression inside the parentheses. For this, we can use methods like grouping or the quadratic formula.

  • Quadratic expression after factoring: 6x2(3−x)(3+5x)6x2(3−x)(3+5x)

Step 3: Final Factorization

Combine the factored common factor with the factored quadratic expression:

  • Final factorization of the given polynomial: 6x2(3−x)(3+5x)6x2(3−x)(3+5x)

    In conclusion, the factorization of the given polynomial expression is 6x2(3−x)(3+5x)6x2(3−x)(3+5x). When considering Class 7 Tuition, online coaching provides a conducive learning environment with personalized attention, flexibility, abundant resources, technology integration, and expert guidance.
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Answered on 26 Feb Learn CBSE/Class 8/Maths/Factorization

Nazia Khanum

As a seasoned tutor registered on UrbanPro.com, I specialize in providing top-notch online coaching for Class 7 Tuition. Today, I'll guide you through the process of factorizing the expression: 2x²yz + 2xy²z + 4xyz. Factorization of 2x²yz + 2xy²z + 4xyz To factorize the given expression,... read more

As a seasoned tutor registered on UrbanPro.com, I specialize in providing top-notch online coaching for Class 7 Tuition. Today, I'll guide you through the process of factorizing the expression: 2x²yz + 2xy²z + 4xyz.


Factorization of 2x²yz + 2xy²z + 4xyz

To factorize the given expression, we'll look for common factors in each term and factor them out.

  1. Identify Common Factors

    • All terms have a common factor of 2.
    • Each term contains a factor of xyz.
  2. Factorize the Expression

    • Factor out the common factor of 2xyz:
      scss
    • 2xyz(x + y + 2)

Explanation

  • Common Factor of 2: Factoring out 2 helps simplify the expression and identify a common factor in each term.

  • Common Factor of xyz: Each term contains a factor of xyz. Factoring this out leaves us with the expression (x + y + 2).

  • Final Factored Expression: Combining the common factors, the fully factorized expression is 2xyz(x + y + 2).

    Conclusion

    Enrolling in the best online coaching for Class 7 Tuition on UrbanPro.com ensures not only academic excellence but also a supportive and enriching learning environment. If you have further questions or need assistance with more topics, feel free to reach out for personalized guidance and effective tutoring.


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Answered on 26 Feb Learn CBSE/Class 8/Maths/Factorization

Nazia Khanum

Greetings! I am an experienced tutor registered on UrbanPro.com, specializing in Class 7 Tuition and online coaching. Below is a detailed explanation of how to factorise the given expression: 30xy – 12x + 10y – 4. Introduction: Understanding Factoring Factorising is a fundamental concept... read more

Greetings! I am an experienced tutor registered on UrbanPro.com, specializing in Class 7 Tuition and online coaching. Below is a detailed explanation of how to factorise the given expression: 30xy – 12x + 10y – 4.

Introduction: Understanding Factoring

Factorising is a fundamental concept in algebra, involving the decomposition of an expression into its constituent factors. In this case, we are tasked with factorising the expression 30xy – 12x + 10y – 4.

Step-by-Step Factoring Process:

  1. Identify Common Factors:

    • Observe the expression and identify common factors shared by all terms.

      Example: 2(15xy−6x+5y−2)2(15xy−6x+5y−2)

  2. Grouping Terms:

    • Group the terms that share common factors.

      Example: 2(15xy−6x)+2(5y−2)2(15xy−6x)+2(5y−2)

  3. Factor Out the Greatest Common Factor (GCF) from Each Group:

    • Factor out the common factor from each group.

      Example: 2⋅3x(5y−2)+2(5y−2)2⋅3x(5y−2)+2(5y−2)

  4. Identify and Factor Out Common Binomial Factor:

    • Notice the common binomial factor in both groups.

      Example: 2(3x+1)(5y−2)2(3x+1)(5y−2)

Conclusion: Factored Expression

By following these steps, the given expression 30xy – 12x + 10y – 4 can be factored as 2(3x+1)(5y−2)2(3x+1)(5y−2).

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Answered on 26 Feb Learn CBSE/Class 8/Maths/Factorization

Nazia Khanum

As an experienced tutor registered on UrbanPro.com, I understand the importance of providing clear and concise explanations to help students grasp challenging concepts. In this response, I will break down the expression "z – 19 + 19xy – xyz" step by step, ensuring a thorough understanding... read more

As an experienced tutor registered on UrbanPro.com, I understand the importance of providing clear and concise explanations to help students grasp challenging concepts. In this response, I will break down the expression "z – 19 + 19xy – xyz" step by step, ensuring a thorough understanding for Class 7 students seeking online coaching.

Step 1: Identify Common Factors

  • Factorizing the expression involves identifying common factors among the terms.

  • Observe that "z" is a common factor in the terms "z" and "-xyz."

    Factorized expression: z(1 - y) - 19 + 19xy

Step 2: Simplify Further

Now, let's simplify the remaining terms.

  1. Combine Like Terms:

    • Combine the constant terms "-19" and the simplified expression "z(1 - y) - 19 + 19xy."

      Simplified expression: z(1 - y) + 19xy - 38

  2. Factorize the Constant Terms:

    • Observe that "19" and "38" have a common factor of 19.

      Simplified and factorized expression: z(1 - y) + 19(x - 2y)

Conclusion:

In conclusion, the expression "z – 19 + 19xy – xyz" can be factorized as follows:

z(1−y)+19(x−2y)z(1−y)+19(x−2y)

For the best understanding and mastery of such concepts, consider enrolling in online coaching for Class 7 Tuition. UrbanPro.com offers a platform where experienced tutors provide comprehensive and personalized guidance to help students excel in their studies. Explore the best online coaching options for Class 7 Tuition on UrbanPro.com to ensure academic success.

 
 
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Answered on 26 Feb Learn CBSE/Class 8/Maths/Factorization

Nazia Khanum

As an experienced tutor registered on UrbanPro.com, I'll guide you through the process of factoring the quadratic expression 100x² – 80xy + 16y². Let's break down the solution into clear steps. Step 1: Identify the Type of Quadratic Expression Before factoring, it's essential to recognize... read more

As an experienced tutor registered on UrbanPro.com, I'll guide you through the process of factoring the quadratic expression 100x² – 80xy + 16y². Let's break down the solution into clear steps.

Step 1: Identify the Type of Quadratic Expression

Before factoring, it's essential to recognize the type of quadratic expression we're dealing with. The given expression is a perfect square trinomial, which can be factored using a specific formula.

Step 2: Apply the Perfect Square Trinomial Formula

The expression 100x² – 80xy + 16y² falls under the category of (a - b)², where 'a' and 'b' are terms in the form of ax and by, respectively. The formula for factoring a perfect square trinomial is:

(a−b)2=a2−2ab+b2(a−b)2=a2−2ab+b2

In our case, a=10xa=10x and b=4yb=4y. Applying the formula:

(10x−4y)2=(10x)2−2(10x)(4y)+(4y)2(10x−4y)2=(10x)2−2(10x)(4y)+(4y)2

Step 3: Simplify the Expression

Now, let's simplify the expression obtained from the formula:

100x2−80xy+16y2100x2−80xy+16y2

=100x2−80xy+16y2=100x2−80xy+16y2

This is the factored form of the given quadratic expression.

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