Saket, Delhi, India - 110017.
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Hindi Mother Tongue (Native)
English Proficient
department of chemistry, delhi university Pursuing
Doctor of Philosophy (Ph.D.)
Saket, Delhi, India - 110017
Landmark: OPPOSITE VIDYA NIKETAN SCHOOL
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Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
3
Board
CBSE, ISC/ICSE, State
ISC/ICSE Subjects taught
Chemistry
CBSE Subjects taught
Chemistry
Taught in School or College
Yes
State Syllabus Subjects taught
Mathematics, Chemistry
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
1. Which school boards of Class 12 do you teach for?
CBSE, ISC/ICSE and State
2. Have you ever taught in any School or College?
Yes
3. Which classes do you teach?
I teach BSc Tuition and Class 12 Tuition Classes.
4. Do you provide a demo class?
Yes, I provide a free demo class.
5. How many years of experience do you have?
I have been teaching for 3 years.
Answered on 19/02/2019 Learn CBSE/Class 11/Science/Chemistry
Answered on 19/02/2019 Learn CBSE/Class 11
when aqueous KOH is used the product formed will be alcohol , it will be a substitution reaction and halide group will be replaced with alcohol group , whereas when alcoholic KOH is used elimination of reaction occurs and product formed will be alkene removal of HBr group from alpha and beta carbon .
1. Propan-1-ol
2.prop-1-ene
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
3
Board
CBSE, ISC/ICSE, State
ISC/ICSE Subjects taught
Chemistry
CBSE Subjects taught
Chemistry
Taught in School or College
Yes
State Syllabus Subjects taught
Mathematics, Chemistry
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Answered on 19/02/2019 Learn CBSE/Class 11/Science/Chemistry
Answered on 19/02/2019 Learn CBSE/Class 11
when aqueous KOH is used the product formed will be alcohol , it will be a substitution reaction and halide group will be replaced with alcohol group , whereas when alcoholic KOH is used elimination of reaction occurs and product formed will be alkene removal of HBr group from alpha and beta carbon .
1. Propan-1-ol
2.prop-1-ene
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