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What will be the acceleration of an elevator of weight 3000 kg, when the tension in the supporting cable is 33000N. (Take, g = 9.8 ms-2)

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Physics Wizard

T=mg+ma , substituting the values and calculating a we get a=1.19m/s. Since the tension in the cable is greater lift is moving upwards and their is upward accelaration
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An elevator weighs 3000kg. What is its acceleration when the in the tension supporting cable is 33000N. Given that g = 9.8m/s2.
M = 3000 kg g = 9.8 m/s² T = 33000 a = ? Ma = Mg - T 3000 * a = 3000 * 9.8 - 33000 3000a = 29400 - 33000 3000a = - 3600 a = - 1.2 m/s².
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